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3 years ago

HELP I'M FAILING ..... so if you have 300 coins and you take away half how much do you have left

Mathematics

2 answers:

My name is Ann [436]3 years ago

8 0

You will have 150 left

Mariulka [41]3 years ago

3 0

150 is your answer

Hope I could help!!!

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NEED HELP ASAP!!! for geometry class

balandron [24]

Answer:

B) AAS

Step-by-step explanation:

B) AAS

5 0

3 years ago

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What is the markup of 23 to 41.40

makkiz [27]

Answer:

80%

Step-by-step explanation:

41.40/23 = 1.8 = 180% = 100% + 80%

The markup is 80%.

8 0

3 years ago

There are 26 students in Jenna's class. Jenna brought in 16 cupcakes. Which equation can be used to find the number of cupcakes

Olin [163]

Answer:

Step-by-step explanation:

16+n=26

26-16=n

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3 years ago

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a store is having a sale on walnuts and chocolate chips. for 3 pounds of walnuts and 5 pounds of chocolate chips, the total cost

Step2247 [10]

Answer:

Walnuts - $1.25, chocolate chips - $3.25

Step-by-step explanation:

Let walnuts = x, chocolate chips = y

Set a system and solve:

3x + 5y = 20
6x + 2y = 14

Double the first equation and subtract the second one from it:

6x + 10y - 6x - 2y = 40 - 14
8y = 26
y = 26/8
y = 3.25

Find the value of x:

6x + 3.25*2 = 14
6x = 14 - 6.5
6x = 7.5
x = 7.5/6
x = 1.25

7 0

2 years ago

Find the area of the shaded region .

Greeley [361]

Calculate area of the white region inside circle.

Area of the two white triangles in top left and bottom right:

$2 \cdot \frac{1}{2}(6)(6) = 36 ft^2$

Area of the two white quarter circles in the bottom left and top right:

$2 \cdot \frac{1}{4}\pi (6)^2 = 18\pi ft^2$

Total area of unshaded white region inside circle:

$(36 + 18\pi)ft^2$

Area of entire circle including the white and shaded regions

$\pi(6)^2 = 36\pi ft^2$

Area of shaded region is area of entire circle - area of unshaded white region

$36\pi - (36 + 18\pi) = (18\pi - 36) ft^2$

7 0

3 years ago