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maks197457 [2]
3 years ago
13

April decided to purchase a $12,000 MSRP vehicle at a 5% interest rate for 4 years. The dealership offered her a $1500 cash-back

incentive, which she accepted. If she takes all these factors into consideration, what monthly payment amount can she expect?
Mathematics
2 answers:
Maksim231197 [3]3 years ago
5 0
10,500÷((1−(1+0.05÷12)^(−12×4))÷(0.05
÷12))=241.81
sergey [27]3 years ago
3 0

Answer:

She can expect the monthly payment of $ 241.81 ( approx )

Step-by-step explanation:

Since,

The original price of the vehicle = $ 12,000

After getting $1500 cash-back incentive,

The price of the vehicle, P.V. = $ 12,000 - $ 1,500 = $ 1,050,

Now, the annual rate = 5 % = 0.05,

⇒ The monthly rate, r = \frac{0.05}{12},

Time = 4 years,

⇒ Number of months, n = 4×12 = 48   ( 1 year = 12 months )

Now, the monthly payment would be,

P=\frac{P.V.(r)}{1-(1+r)^{-n}}

=\frac{10500(\frac{5}{1200})}{1-(1+\frac{5}{1200})^{-48}}

=\$241.807582492\approx \$ 241.81

Hence, she can expect the monthly payment of $ 241.81.

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4 0
3 years ago
Felicia bought 3 feet of ribbon for a project. she needs to cut the ribbon into 6 equal pieces. how long will each ribbon be?
anastassius [24]
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3 years ago
Do any of you know how to do this
Gre4nikov [31]

Answer:

(x + 5)

Step-by-step explanation:

{x}^{2}  + 8x + 15 \\  {x}^{2}  + 3x + 5x + 15 \\ x(x + 3)5(x + 3) \\ (x + 3)(x + 5) \\ length \:  =  \frac{(x + 3)(x + 5)}{(x + 3)}  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = (x  + 5)

5 0
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Read 2 more answers
An open box is to be constructed so that the length of the base is 3 times larger than the width of the base. If the cost to con
natta225 [31]

Answer:

Step-by-step explanation:

Let assume that the volume = 88 cubic feet

Then:

L = 3w --- (1)volume = l \times w \times h \\ \\ 88 =  (3w)   \times w  \times h \\ \\ 3w^2 h= 88 \\ \\ h = \dfrac{88}{3w^2}--- (2) \\ \\

The construction cost now is:

C = 4(l \times w) + 2 ( w  \times h) + 2(l \times h) \\ \\ C = 4(3w^2) + 2(w  \times \dfrac{88}{3w^2}) + 2(3w \times \dfrac{88}{3w^2}) \\\\ C = 12w^2 + \dfrac{176}{3w} + \dfrac{176}{w}

Now, to determine the minimum cost:

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w = \dfrac{88}{3(3)}^{1/3} \ feet

Now;

length = 3 ( \dfrac{88}{3(3)})^{1/3} \ feet

height = ( 88})^{1/3} (3)^{1/3} \ feet

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