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3 years ago

Need help need help need help need help

Mathematics

2 answers:

BartSMP [9]3 years ago

6 0

Answer:

Step-by-step explanation:

I believe that since both circles C & D are congruent, and TU is bisected into TW and WU, PS = 7.4/2 = 3.7

PS = 3.7

san4es73 [151]3 years ago

3 0

Answer:

it is 6.9

Step-by-step explanation:

i took the test

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What's 7% of 24,678?

Anuta_ua [19.1K]

U just do 24,678 * .07 to get <span>1727.46</span>

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4 years ago

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AysviL [449]

Answer:

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3 years ago

5y - 4x = -7<br> 2y + 4z = 14<br> Solve for x and y

castortr0y [4]

Answer:

et's solve for x.

5y−4x=−72y+4z

Step 1: Add -5y to both sides.

−4x+5y+−5y=−72y+4z+−5y

−4x=−77y+4z

Step 2: Divide both sides by -4.

−4x

−4

−77y+4z

−4

y−z

Answer:

y−z

Let's solve for y.

5y−4x=−72y+4z

Step 1: Add 72y to both sides.

−4x+5y+72y=−72y+4z+72y

−4x+77y=4z

Step 2: Add 4x to both sides.

−4x+77y+4x=4z+4x

77y=4x+4z

Step 3: Divide both sides by 77.

77y

4x+4z

Answer:

Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

The figure below shows square ABCD inscribed on square PQRM on a coordinate plane. Which of the following expressions represents

vova2212 [387]

The hypotenuse of the triangle is given by:
$CB ^ 2 = RC ^ 2 + RB ^ 2
$
Substituting values:
$CB ^ 2 = 2 ^ 2 + 4 ^ 2
$
Clearing CB we have:
$CB = \sqrt{ 2 ^ 2 + 4 ^ 2} 

 CB = \sqrt{ 4 + 16} 

 CB = \sqrt{20} 

 CB = \sqrt{4*5} 

 CB = 2\sqrt{5} 



$
Then, the perimeter of the triangle is:
$P = RB + RC + CB
$
Substituting values:
$P = 4 + 2 + 2 \sqrt{5} 

 P = 6 + 2 \sqrt{5}$
Answer:
the perimeter of triangle BRC in units is:
D.6 + 2√5

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3 years ago

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Is .277277277 irrational

prisoha [69]

Nope. Your problem is not irrational

4 0

3 years ago