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PilotLPTM [1.2K]
3 years ago
10

Is .277277277 irrational

Mathematics
1 answer:
prisoha [69]3 years ago
4 0
Nope. Your problem is not irrational
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a used truck for $4,500 he made an agreement with the dealer to put $1,500 and make payments of 350 for the next 10 months that
Aneli [31]
Ist amount paid = $1500
Making $350 for 10 months = 10*350 = $3500
Total amount paid  = 1500 + 3500 = 5000
So an amount of $5000 was paid to cover the cost of $4500 within the ten month period.
I = PRT
Interest, I = 5000 - 4500 = 500Time, t = 10 months = 10/12 = (5/6) year.Principal P = 4500
R = I /(PT)  R = 500 / (4500*5/6)
R = (500*6) / (4500*5)
R = 0.1333..
R ≈ 13.33 %  per annum.

3 0
3 years ago
0.16666666666 as a fraction
Ira Lisetskai [31]
The correct answer is <span>16666666666/100000000000.</span>
4 0
3 years ago
Read 2 more answers
Use a matrix to solve the system:
Romashka-Z-Leto [24]

Answer:

(2.83 , 1 , 4)

Step-by-step explanation:

2x+2y-z=4\\4x-2y-2z=2\\3x+3y-4z=-4\\

Rewrite these equations in matrix form

\left[\begin{array}{ccc}2&2&-1\\4&-2&-2\\3&3&-4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\

we can write it like this,

AX=B\\X=A^{-1}B

so to solve it we need to take the inverse of the 3 x 3 matrix A then multiply it by B.

We get the inverse of matrix A,

A^{-1}=\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]  \\

now multiply the matrix with B

X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2.83\\1\\4\end{array}\right] \\

4 0
3 years ago
5-2(x+5)=3x-15 solve for X
Maslowich

Answer:

x= 2

Step-by-step explanation:

5 -2(x +5)= 3x -15

Expand:

5 -2x -2(5)= 3x -15

5 -2x -10= 3x -15

Simplify:

-2x -5= 3x -15

Bring x terms to 1 side, constant to the other:

3x +2x= 15 -5

5x= 10

Divide both sides by 5:

x= 10 ÷5

x= 2

8 0
3 years ago
Read 2 more answers
Which of the following is not a condition that must be met before you can use the quadratic formula to find the solutions of an
77julia77 [94]
The second choice is the correct one
7 0
3 years ago
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