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PilotLPTM [1.2K]
3 years ago
10

Is .277277277 irrational

Mathematics
1 answer:
prisoha [69]3 years ago
4 0
Nope. Your problem is not irrational
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Lesson 2-3
malfutka [58]

Answer:

18. g= -3

19. x= -1

20. n= 3

21. p= -1

22. d= -3

23. a= 5

Step-by-step explanation:

how to solve the variable (using 18 as an example)

step 1: simplify both sides of the equation.

20+g+g=14

(g+g)+(20)=14(combine like terms)

2g+20=14

2g+20=14

step 2: subtract 20 from both sides.

2g+20−20=14−20

2g=−6

step 3: divide both sides by 2.

2g/2 = -6/2

6 0
3 years ago
If h(x)=1/2x - 8, find h(4).​
patriot [66]

Answer:

h(4) = 1/2 (4) - 8 = 2 - 8 = -6

Step-by-step explanation:

5 0
3 years ago
Which angle measures create a triangle with three different side lengths?
kenny6666 [7]

13°, 66°, and 101° ......

8 0
3 years ago
Graph quadrilateral ABCD with vertices A(2,-3), B(3,5), C(6,6) and D(5,-3) and its image after the translation (x,y)→(x−5,y−2)
maria [59]

The graph can be drawn by the placing the points and after translation points becomes A'(-3, -5), B'(-2, 3), C'(1, 4), and D'(0, -5)

<h3>What is quadrilateral?</h3>

It is defined as the four-sided polygon in geometry having four edges and four corners.

We have:

Quadrilateral ABCD with vertices A(2,-3), B(3,5), C(6,6) and D(5,-3)

We can graph it on the coordinate plane as shown in the picture.

After applying the translation (x, y)→(x−5, y−2), the points becomes:

A'(-3, -5)

B'(-2, 3)

C'(1, 4)

D'(0, -5)

Similarly, we can graph it on the coordinate plane (refer attached picture)

Thus, the graph can be drawn by the placing the points and after translation points becomes A'(-3, -5), B'(-2, 3), C'(1, 4), and D'(0, -5)

Learn more about the quadrilateral here:

brainly.com/question/6321910

#SPJ1

6 0
2 years ago
Whats the answer &amp; how do I solve it ?
Veseljchak [2.6K]

Answer:

Area of rectangle = 225/2 or 112.5

Step-by-step explanation:

Given,

Consider a rectangle ABCD.

Let AC be a diagonal of rectangle of length   = 15

In triangle  ABC.

Sin 45° =height/hypotenuse   {SinФ = height / hypotenuse}

Here, hypotenuse = diagonal of rectangle ( i.e AC = 15)

And height is AB

Therefore, sin 45° = AB/AC

or sin 45° = AB / 15

or 1/√2 = AB /15

AB = 15/√2

Similarly we can find Base (i.e BC) using cosine.

Cos 45° = Base/Hypotenuse

Cos 45° = BC / AC

or  1/√2 = BC/15

BC = 15/√2

Hence we got length of rectangle , AB= 15/√2

And width of rectangle , BC = 15/√2

Therefore, area of rectangle = Length × Width

Area of rectangle = 15/√2  ×   15/√2  = 225/2

Hence, area of rectangle = 225/2 = 112.5

6 0
3 years ago
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