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3 years ago

14

Traci starts running on a trail and can run a mile in 10 minutes. Hannah starts running from the same spot 20 minutes after Trac

i. If Hannah can run a mile in 8 minutes, how many miles would she have to run to catch up with Traci?

1 answer:

Setler [38]3 years ago

8 0

Answer:

Yoni will catch Traci after 20 minutes.

Step-by-step explanation:

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3.15 dollar you gonna get back

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consider the function f(x) = x2 2x – 15. what are the x-intercepts of the function? left-most x-intercept: ( , 0) right-most x-i

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we have

$f(x)=x^{2} +2x-15$

we know that

The x-intercept is the value of x when the value of the function is equal to zero

so

in this problem

Find the roots of the function

equate the function to zero

$x^{2} +2x-15=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2} +2x=15$

Complete the square. Remember to balance the equation by adding the same constants to each side

$x^{2} +2x+1=15+1$

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Rewrite as perfect squares

$(x+1)^{2}=16$

Square root both sides

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<u>the answer is</u>

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Help! I have looked at so many lessons on writing exponential functions from a graph and nothing has helped.

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Answer:

y = $8(-\frac{1}{2})^x$

Step-by-step explanation:

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y = a(b)ˣ

Since the graph of this function passes through two points $(4, \frac{1}{2})$ and (3, -1)

For the point $(4, \frac{1}{2})$ ,

$\frac{1}{2}=a(b)^4$ ---------(1)

For second point (3, -1),

-1 = a(b)³ ---------(2)

Divide equation (2) by equation (1),

$\frac{\frac{1}{2}}{-1}$ = $\frac{a(b)^4}{a(b)^3}$

$-\frac{1}{2}=b^{(4-3)}$

$-\frac{1}{2}=b$

From equation (2)

-1 = $a(-\frac{1}{2})^3$

-1 = $-\frac{1}{8}a$

a = 8

Therefore, equation of the exponential function will be,

y = $8(-\frac{1}{2})^x$

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