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Resolve 3x-1÷(x+1)^2 into partial fraction
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Answer:
2
Step-by-step explanation:
A commutative function means that when you insert one function in space of x in the other function, they will equal x. The equation is f(g(x)) = g(f(x)) = x
So, 2() - 1 =
If you multiply both sides by <em>a</em>, you get 2<em>a</em>() - a = (2x-1)+1
Simplify it 2<em>a</em>() - <em>a</em> = 2x
Add <em>a</em> to both sides 2<em>a</em>() = 2x +<em>a</em>
The two <em>a</em>s on the left cancel out 2(x+1)=2x+<em>a</em>
Distribute the 2 2x+2=2x+<em>a</em>
Then subtract 2x from both sides 2 = <em>a</em>
Therefore, <em>a</em> = 2
Hope this helps!