Resolve 3x-1÷(x+1)^2 into partial fraction
1 answer:
9514 1404 393
Answer:
3/(x +1) -4/(x +1)^2
Step-by-step explanation:
The partial fraction expansion will be of the form ...
A/(x+1)^2 +B/(x+1)
We can find the values of A and B by writing the sum of these terms:
= (A +B(x +1))/(x +1)^2
Then we require ...
B = 3
A +B = -1 ⇒ A = -4
So, the desired expansion is ...
3/(x +1) -4/(x +1)^2
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