Answer: admission cost is 21 dollars
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given data:
Circumference of the base of the cone = 24in.
Recall that circumference (in this case) is the distance round the base of the cone and from here the diameter D=12in. Radius = 6in
Surface area l = pie x radius ( slant height + radius)
= 3.142 x 6 (20 + 6)
= 3.142 x 6 (26)
= 3.142 x 156
= 490.152in^2
Answer:
3.16 units
Step-by-step explanation:
It has been given that the triangles JKL and the triangle RST are congruent.
That implies that, the length of the side JK, KL, and JL is equivalent to the length of the sides RS, ST, and RT respectively.
Now, to find the length of JK we need to find the length of the side RS. The coordinates of the points R and S are
and
.
The length of the side RS is equal to the distance between point R and S.
RS 



Now that we have the length of the side RS, and the triangles JKL and RST are congruent therefore, the length of the side JK is 3.16 units.
D= # of dimes
q= # of quarters
QUANTITY EQUATION:
d + q= 64
COST EQUATION:
0.10d + 0.25q= $9.25
STEP 1:
multiply quantity equation by -0.10 to be able to eliminate the d term in step 2
(-0.10)(d + q)= (-0.10)(64)
-0.10d - 0.10q= -6.40
STEP 2:
add equation from step 1 to cost equation to eliminate the d term and solve for q
Add
0.10d + 0.25q= $9.25
-0.10d - 0.10q= -6.40
0.15q= 2.85
divide both sides by 0.15
q= 19 quarters
STEP 3:
substitute q value in step 2 into either original equation to find d value
d + q= 64
d + 19= 64
subtract 19 from both sides
d= 45 dimes
CHECK:
0.10d + 0.25q= $9.25
0.10(45) + 0.25(19)= 9.25
4.50 + 4.75= 9.25
9.25= 9.25
ANSWER: There are 45 dimes and 19 quarters.
Hope this helps! :)
Answer:
(12,-6)
Step-by-step explanation:
we have
----> inequality A
---> inequality B
we know that
If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)
<u><em>Verify each point</em></u>
Substitute the value of x and the value of y of each ordered pair in the inequality A and in the inequality B
case 1) (0,-1)
Inequality A

----> is true
Inequality B

----> is not true
therefore
The ordered pair is not a solution of the system
case 2) (0,3)
Inequality A

----> is true
Inequality B

----> is not true
therefore
The ordered pair is not a solution of the system
case 3) (-6,-6)
Inequality A

----> is true
Inequality B

----> is not true
therefore
The ordered pair is not a solution of the system
case 4) (12,-6)
Inequality A

----> is true
Inequality B

----> is true
therefore
The ordered pair is a solution of the system (makes true both inequalities)