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choli [55]
3 years ago
8

If the average adult produces $110,000 of output per year, how much output is lost annually as a result of adult deaths from sec

ondhand smoke?
Mathematics
1 answer:
posledela3 years ago
3 0
The answer to the given question above would be <span> $47,859,000,000 or $48 billion. Given that the average </span>adult produces $110,000 of output per year, the amount of output that is <span> lost annually as a result of adult deaths from secondhand smoke is $48 billion. 
</span>600,000 total deaths 
<span>165,000 children </span>
<span>435,000 adults </span>
<span>435,00 times $110,00 output per year = $47,859,000,000
</span>Hope this helps.
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VladimirAG [237]
Okay one moment i will have the answer soon...
3 0
3 years ago
Read 2 more answers
Question 1 (3 points)
Basile [38]

Answer:

The mean is 12, The median is 13, The mode is 14, and the range is 8.

The second choice is the correct answer.

Explanation:

  1. I found the mean by adding up all the numbers and dividing by the number of numbers, or sun divided by count. The sum of the numbers was 132, and the count was 11. I divided 132 by 11 to get 12.
  2. I listed the numbers in order from least to greatest. The data set was: 7, 8, 10, 12, 12, 13, 13, 14, 14, 14, 15
  3. I found the median by crossing off the number on each end of the data set, and kept going. For example, I crossed off 8, and then 15, and then 10, and then 14 and so on until I got to the middle number. (Keep in mind, if there are two middle numbers, find the mean of them [add them and divide by two])
  4. The mode is the number that shows up the most in the data set, so I looked at the data set and saw that 14 showed up 3 times, more times than any other number.
  5. The range is the difference between the greatest and least number (maximum and minimum) so I just subtracted 15 - 7 to get a difference of 8.
6 0
3 years ago
Find the standard deviation of the following data. Round your answer to one decimal place. x 0 1 2 3 4 5 P(X
lbvjy [14]

Answer:

<em></em>\sigma = 1.8<em></em>

<em></em>

Step-by-step explanation:

Given

\begin{array}{ccccccc}x & {0} & {1} & {2} & {3} & {4}& {5} \ \\ P(x) & {0.2} & {0.1} & {0.1} & {0.2} & {0.2}& {0.2} \ \end{array}

Required

The standard deviation

First, calculate the expected value E(x)

E(x) = \sum x * P(x)

So, we have:

E(x) = 0 * 0.2 + 1 * 0.1 + 2 * 0.1 + 3 * 0.2 + 4 * 0.2 + 5  * 0.2

E(x) = 2.7

Next, calculate E(x^2)

E(x^2) = \sum x^2 * P(x)

So, we have:

E(x^2) = 0^2 * 0.2 + 1^2 * 0.1 + 2^2 * 0.1 + 3^2 * 0.2 + 4^2 * 0.2 + 5^2  * 0.2

E(x^2) = 10.5

The standard deviation is:

\sigma = \sqrt{E(x^2) - (E(x))^2}

\sigma = \sqrt{10.5 - 2.7^2}

\sigma = \sqrt{10.5 - 7.29}

\sigma = \sqrt{3.21}

<em></em>\sigma = 1.8<em> --- approximated</em>

5 0
3 years ago
The number of loaves of bread purchased and the total cost of the bread in dollars can be modeled by the equation c = 3. 5b. Whi
Allisa [31]

You can use the fact that number of breads purchased cannot be negative since a customer either buys them or not and usually do not sell to the shopkeeper.(if somehow they end up selling to shop owner, then yes that will go in negative, but we'll assume it is wrong in most cases as generally shop owners are there to sell stuffs).

The third table of values matches the equation and includes only viable solutions.

<h3>What is a viable solution here?</h3>

It is talking about those solutions which are seen in real world. As stated above, a customer either buys the bread or not, thus number of breads sold will be either positive or 0(in case of no selling). Thus, we cannot have number of breads as negative.

Such solutions which are correct in the real world context here are called here as viable solutions.

<h3>Checking one by one all the tables for them being matched with table and viability</h3>

For first table, the number of breads are in negative, thus it is not going to have viable solution.

For second table, we have:

b = 0 thus c = 3.5b = 3.5 times 0 = 0 which is correctly given in second column.

b = 0.5, thus c = 3.5b = 3.5 times 0.5 =1.75 which is correctly given.

b = 1, thus c= 3.5 times 1 = 3.5 which is correctly given

b = 2001.5 thus c = 3.5 times 2001.5  = 7005.25 which is not correctly given, thus wrong.

For third table, we have:

b = 0, thus c = 3.5 \times 0 = 0, correctly given in second column.

b = 3, thus c = 3.5 \times 3 = 10.5, correctly given.

b = 6, thus c = 3.5 \times 6 = 21, correctly given.

b = 9, thus c = 3.5 \times 9 = 31.5, correctly given.

Thus, the third table of values matches the equation and includes only viable solutions.

Learn more about purchasing to cost relation here:
brainly.com/question/13727919

8 0
3 years ago
Evaluate 105*95 using identities
Nikolay [14]

Answer:

9975

Step-by-step explanation:

See attachment.

( 105 ) * ( 95 )

(100+5) * (100-5)

100*100 * (1 + 5/100) * ( 1 - 5/100)

10000 * ( 1 - 5/100 + 5/100 - {25/10000} )

- 5/100 + 5/100, they cancel each other out to 0

10000 * ( 1 + 0 - {25/10000} )

10000 * ( 1 - {25/10000} )

10000 - {25*10000/10000}

10000 - {25}

9975

6 0
3 years ago
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