2 times 10 equals 20
208 divided by 20 equals 10.4
 
        
             
        
        
        
(2x-y)+(3y-x) = 2y+X = 25
25 = 2:1 = 2Y:X
25/3 = 25/3
25/3 * 2 = 50/3 = 2y
x = 25/3
y = 25/3
Hope this helps! :)
        
             
        
        
        
Answer:
x-coordinates of relative extrema = 
x-coordinates of the inflexion points are 0, 1
Step-by-step explanation:

Differentiate with respect to x


Differentiate f'(x) with respect to x

At x =  ,
,

We know that if  then x = a is a point of minima.
 then x = a is a point of minima.
So,  is a point of minima.
 is a point of minima.
For inflexion points:
Inflexion points are the points at which f''(x) = 0 or f''(x) is not defined.
So, x-coordinates of the inflexion points are 0, 1
 
        
             
        
        
        
Sin2x = 2sinxcosx;
cos2x = (cosx)^2 - (sinx)^2;
tan2x = (sin2x)/(cos2x);
 cosx = 5/13 from formula (sinx)^2 + (cosx)^2 = 1;
=> sin2x = 120/169; 
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Answer:
∠AEC = 139°
Step-by-step explanation:
Since EC bisects ∠BED then ∠BEC = ∠CED = 4x + 1
∠AED = ∠AEB + ∠BEC + ∠CED = 180 ← straight angle
Substitute values into the equation
11x - 12 + 4x + 1 + 4x + 1 = 180, that is
19x - 10 = 180 ( add 10 to both sides )
19x = 190 ( divide both sides by 19 )
x = 10
Hence
∠AEC = ∠AEB + ∠BEC = 11x - 12 + 4x + 1 = 15x - 11, hence
∠AEC = (15 × 10) - 11 = 150 - 11 = 139°