Which pair of triangles can be proven congruent by SAS?
1 answer:
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Answer:
1/30 of a ton
Step-by-step explanation:
Write this as an expression:
1/3 of a ton and 1/2 of a ton were taken to the site.
4/5 of a ton were remove from the site.
Amount of a ton at the site =
Solve the equation by finding <u>common denominators</u> (when the bottom numbers are the same).
Focus on the first part. The least common multiple (LCM) of 3 and 2 is "6", which will become the denominator.
For <u>1/3 to become ?/6</u>, multiply top and bottom by 2.
For <u>1/2 to become ?/6</u>, multiply top and bottom by 3.
Now we can add the numerators together over the same denominator.
Do the same thing as before and change the denominators. The LCM of 6 and 5 is "30".
For <u>5/6 to become ?/30</u>, multiply top and bottom by 5.
For <u>4/5 to become ?/30</u>, multiply top and bottom by 6.
Subtract the numerators:
Answer in tons
Therefore there was 1/30 of a ton of rock left at the construction site.
Answer:
The 38th term of 459,450,441,.. will be:
Step-by-step explanation:
Given the sequence
An arithmetic sequence has a constant difference 'd' and is defined by
computing the differences of all the adjacent terms
so
The first element of the sequence is
so the nth term will be
Putting n=38 to find the 38th term
Therefore, the 38th term of 459,450,441,.. will be: