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Anna35 [415]
3 years ago
10

Which pair of triangles can be proven congruent by SAS?

Mathematics
1 answer:
LuckyWell [14K]3 years ago
8 0

Answer:2nd one starting from top left

Step-by-step explanation:

there r two sides congruent and an angle in between

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How can I do this ???​
LuckyWell [14K]

Answer:

The triangle EFG can be constructed with the following specifications: EF = 8\,cm, FG = 7\,cm, EG = 12\,cm, E \approx 34.093^{\circ}, F \approx 106.068^{\circ}, G \approx 39.838^{\circ}.

Step-by-step explanation:

A triangle is formed by either knowing the lengths of its three sides or knowing two angles and the length of a side or knowing a angle and the lengths of two sides. By Geometry, we know that sum of internal angles in triangles equals 180°. In order to construct this triangle, we need to know the measures of angles E, F and G by means of the Law of Cosine:

Angle E

E = \cos^{-1}\left[\frac{(7\,cm)^{2}-(12\,cm)^{2}-(8\,cm)^{2}}{-2\cdot (12\,cm)\cdot (8\,cm)} \right]

E \approx 34.093^{\circ}

Angle F

F = \cos^{-1}\left[\frac{(12\,cm)^{2} - (8\,cm)^{2} - (7\,cm)^{2}}{-2\cdot (8\,cm)\cdot (7\,cm)} \right]

F \approx 106.068^{\circ}

Angle G

G = \cos^{-1}\left[\frac{(8\,cm)^{2}-(12\,cm)^{2}-(7\,cm)^{2}}{-2\cdot (12\,cm)\cdot (7\,cm)} \right]

G \approx 39.838^{\circ}

The triangle EFG can be constructed with the following specifications: EF = 8\,cm, FG = 7\,cm, EG = 12\,cm, E \approx 34.093^{\circ}, F \approx 106.068^{\circ}, G \approx 39.838^{\circ}.

4 0
2 years ago
Need help how to solve this
kow [346]

x=0 because 0-9 = -9

3 0
3 years ago
Read 2 more answers
RATING BRAINLIEST Which of the following demonstrates the Distributive Property?
ra1l [238]

Answer:

D: 4(2a+3)=8a+3

Step-by-step explanation:

4x2a = 8a and 4x3 = 12

4 0
1 year ago
Read 2 more answers
A plumber charges of fee of $75 to make a house call. He also charges $50 per hour for labor.
Hoochie [10]

Answer:

For part 1- y=50x+75 For part 2- y=325

Step-by-step explanation:

the cost is increasing 50 for every hour

there is a flat rate of 75 to answer a house call

y=50x+75

y=50(5)+75

y=250+75

y=325

5 0
2 years ago
Kate gave 5/6 of her CDs to Sue. Sue gave 7/8 of these to Joan. Joan gave 3/5 of these to Ann. Ann received 70 CDs how many did
olya-2409 [2.1K]
Let us assume the number of CDs Kate had = x
Number of CDs given to Sue = 5x/6
Number of CDs given to Joan = (5x/6) * ( 7/8)
                                                = 35x/48
Number of CDs given to Ann = (35x/48) * (3/5)
                                              = 7x/16
Total number of CDs Ann received = 70
Then
7x/16 = 70
x = 160
From the above deduction, it can be concluded that the number of CDs that Kate originally had was 160. I hope that this is the answer that has actually come to your help.
5 0
3 years ago
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