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3 years ago

What is 3x9x-5x=7#hh&

Mathematics

1 answer:

Paha777 [63]3 years ago

7 0

move the 3 to the 7 side. it will become negative.

9x-5x=7-3

4x=4

x=1

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Stan a local delivery driver is paid $3.50 per mile driven plus a daily amount of $75. on monday he is assigned a route that is

ozzi

So find the numbers it gives you
3.50$/per mile +75$
30 miles
per means multiply
(3.50*30)+75
105.00+75
he is paid 180.00$ for driving on monday

7 0

4 years ago

What is the distance between the point (10,12) and (-4,-36)

dimulka [17.4K]

Well using distance formula

$d \: = \sqrt{(x {}^{2} } - x {}^{1} ) + (y {}^{2} + y {}^{1} )$
The answer I got was Distance = 45.9 what ever unit of measure it might ask for. Feel free to check my math just in case.

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3 years ago

After 3.5 hours pasha had traveled to 17 miles if she travels at a constant speed how far will she have traveled after four hour

laiz [17]

Since we want to know how far she goes every hour to multiply that by 4 to get how far she goes in 4 hours, we do 17/3.5 to get per hour miles = around 4.86. Multiply that by 4 to get around 19.43 miles

4 0

3 years ago

Slove the quadratic by factoring <br><br>x²-3x-16=-6

creativ13 [48]

Answer:

x^(2)-3x-16=7x

Step-by-step explanation:

3 0

3 years ago

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

Zina [86]

Answer:

Step-by-step explanation:

The given differential equation is:

$x^3y'' + 2x^2y' + 4y$

the main task here is to determine the singular points of the given differential equation and Classify each singular point as regular or irregular.

So, for a regular singular point ; $x=x_o$ is located at the first power in the denominator of P(x) likewise at the Q(x) in the second power of the denominator. If that is not the case, then it is termed as an irregular singular point.

Let first convert it to standard form by dividing through with x³

$y'' + \dfrac{2x^2y'}{x^3} + \dfrac{4y}{x^3} =0$

$y'' + \dfrac{2y'}{x} + \dfrac{4y}{x^3} =0$

The standard form of the differential equation is :

$\dfrac{d^2y}{dy} + P(x) \dfrac{dy}{dx}+Q(x)y =0$

Thus;

$P(x) = \dfrac{2}{x}$

$Q(x) = \dfrac{4}{x^3}$

The zeros of $x,x^3$ is 0

Therefore , the singular points of above given differential equation is 0

Classify each singular point as regular or irregular.

Let p(x) = xP(x) and q(x) = x²Q(x)

p(x) = xP(x)

p(x) = $x*\dfrac{2}{x}$

p(x) = 2

q(x) = x²Q(x)

q(x) = $x^2 * \dfrac{4}{x^3}$

q(x) = $\dfrac{4}{x}$

The function (f) is analytic if at a given point a it is represented by power series in x-a either with a positive or infinite radius of convergence.

Thus ; from above; we can say that q(x) is not analytic at x = 0

$Q(x) = \dfrac{4}{x^3}$ do not satisfy the condition,at most to the second power in the denominator of Q(x).

Thus, the point x =0 is an irregular singular point

6 0

3 years ago