All categories

3 years ago

II

Mathematics

1 answer:

kati45 [8]3 years ago

5 0

The answer will be 0;7 and 2;112.

You might be interested in

Given the function f(x)=x2+2x, the value of f(4) is

Citrus2011 [14]

Answer:

Step-by-step explanation:

f(x)=x^2+2x

Let x= 4

f(4)=4^2+2*4

= 16 + 8

= 24

5 0

3 years ago

Solve for Xin the equation x^2-12+36=90

Hunter-Best [27]

X= + or- square root 66 i solved using the pq formula but u can also use the quadratic formula as well and the square root formula but I'ma show u how to solve it with pq it's on this image hope it helps and mark me brainliest

7 0

3 years ago

Read 2 more answers

Write the data set that is shown on the dot plot in ascending order.

Lady_Fox [76]

Answer:

Step-by-step explanation:

1,2,3,3,3,3,5,6,7,10,10,10,11,11,12,12,13,13,

14,15

5 0

3 years ago

if there are more students in one group than the other would it be possible to have equal proportions?

coldgirl [10]

Yes but In the bigger group each person would have less

3 0

3 years ago

Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 90.5 N , Jill pul

Radda [10]

Answer:

Fn= 174.9 N : Magnitude of the net force the people exert on the donkey.

Step-by-step explanation:

We find the components of the forces in x-y-z

Force of Jack in z =F₁z=90.5 N in direction (+z)

Force of Jill in x = F₂x= -82.3*cos45°= - 58.19 N (-x)

Force of Jill in y =F₂y=-82.3*sin45°= + 58.19 N (+y)

Force of Jane in x =F₃x=125*cos45°= + 88.4 N (+x)

Force of Jane in y =F₃y=125*sin45°= + 88.4 N (+y)

Calculating of the components of the net force the people exert on the donkey.

Fnx= F₂x+F₃x=( - 58.19+ 88.4 )N=30.2N (+x)

Fny= F₂y+F₃y=( 58.19+88.4 ) = 146.59 N (+y)

Fnz =F₁z=90.5 N (+z)

Calculating of the magnitude of the net force the people exert on the donkey.

$F_{n} =\sqrt{(F_{nx})^{2}+(F_{ny}) ^{2} +(F_{nz}) ^{2} }$

$F_{n} =\sqrt{(30.2)^{2}+( 146.59) ^{2} +(90.5) ^{2} }$

$F_{n} = 174.9 N$

7 0

3 years ago