All categories

3 years ago

Can you please solve this pllleeaasseee??

Mathematics

2 answers:

gizmo_the_mogwai [7]3 years ago

6 0

I think she can use it 8 times

dimaraw [331]3 years ago

4 0

Answer :

Part 5 :

The number of sundaes used for 16 ounces of chocolate syrup are, 80

Part 6 :

The pipe B is longer by 679.25 m than pipe A.

Step-by-step explanation :

Given:

Amount of chocolate syrup on each sundae = 0.2 ounce

Now we have to determine the number of sundaes used for 16 ounces of chocolate syrup.

As, 0.2 ounce chocolate syrup used for = 1 sundae

So, 16 ounces chocolate syrup used for = $\frac{16}{0.2}$ sundae

= 80 sundaes

Thus, the number of sundaes used for 16 ounces of chocolate syrup are, 80

Length of pipe A = 70.75 m

Length of pipe B = 0.75 km

First we have to convert length of pipe B from km to m.

Conversion used :

1 km = 1000 m

As, 1 km = 1000 m

So, 0.75 km = 750.00 m

From this we conclude that, the pipe B is longer than pipe A.

Difference of both pipe = Length of pipe B - Length of pipe A

Difference of both pipe = 750.00 m - 70.75 m

Difference of both pipe = 679.25 m

Hence, the pipe B is longer by 679.25 m than pipe A.

You might be interested in

Please help this is not possible

Reika [66]

Answer:

-3x - 10x - 16 29/x-2

Step-by-step explanation:

set up the synthetic division using the coefficients of the numerator and the root in the denominator. Divide using the rules for synthetic division

8 0

3 years ago

Solve the system by elimination

Alja [10]

First of all we will eliminate x from our equations. In order to do that we will use our first and second equation and then we will use second and third equation.

$-2x+2y+3z=0...(1)\\-2x-y+z=-3....(2)$

Upon subtracting 2 equation from 1 we will get,

$3y+2z=3....(4)$

Now we will use second and third equation to eliminate x.

$-2x-y+z=-3....(2)\\2x+3y+3z=5....(3)$

Adding 2nd and 3rd equation we will get,

$2y+4z=2....(5)$

Now we will find out y from our 4th and 5th equation.

$2*(3y+2z)=2*3....(4)\\2y+4z=2....(5)$

Upon subtracting 5th equation from 4th equation we will get,

$4y=4\\y=1$

Now let us find out z by substituting y's value in 5th equation.

$2*1+4z=2\\4z=2-2\\z=0$

Now we will find x from by substituting y and z's value in equation 1.

$-2x+2*1+3*0=0\\-2x+2=0\\2=2x\\x=1$

Therefore, x=1, y=1 and z=0 is the solution of the given system.

3 0

4 years ago

The height of a triangle is 8cm more than the base. If the area is 90cm^2, find the base and the height

Aleonysh [2.5K]

I get the base to be 4.74 and the height to be 12.74

3 0

3 years ago

Why was the incident between Mack and Morris is called a massacre ?

Gekata [30.6K]

Answer:

because one or the other ended up dead

Step-by-step explanation:

3 0

4 years ago

Suppose a normal distribution has a mean of 62 and a standard deviation of 4. What is the probability that a data value is betwe

Anon25 [30]

Answer:Given a normal distribution with μ = 62 and σ = 4., calculate the 68-95-99.7 rule, or three-sigma rule, or empirical rule ranges

Calculate Range 1:

Range 1, or the 68% range, states that 68% of the normal distribution values lie within 1 standard deviation of the mean

68% of values are within μ ± σ

μ ± σ = 62 ± 4.

62 - 4. <= 68% of values <= 62 + 4.

58 <= 68% of values <= 66

Calculate Range 2:

Range 2, or the 95% range, states that 95% of the normal distribution values lie within 2 standard deviations of the mean

95% of values are within μ ± 2σ

μ ± 2σ = 62 ± 2(4.)

62 - 2 x 4. <= 95% of values <= 62 + 2 x 4.

62 - 8 <= 95% of values <= 62 + 8

54 <= 95% of values <= 70

Calculate Range 3:

Range 3, or the 99.7% range, states that 99.7% (virtually ALL) of the normal distribution values lie within 3 standard deviations of the mean

99.7% of values are within μ ± 3σ

μ ± 3σ = 62 ± 3(4.)

62 - 3 x 4. <= 99.7% of values <= 62 + 3 x 4.

62 - 12 <= 99.7% of values <= 62 + 12

50 <= 99.7% of values <= 74

Step-by-step explanation:

4 0

2 years ago