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QveST [7]
3 years ago
12

A model rocket is launched from ground level. Its height, h meters above the ground, is a function of time t seconds after launc

h and is given by the equation . What would be the maximum height, to the nearest meter, attained by the model? (First find the axis of symmetry x= (-b/2a), then plug this value into the equation)
Mathematics
1 answer:
musickatia [10]3 years ago
3 0

Answer:

The maximum height attained by the rocket is 240.1 m.

Step-by-step explanation:

The height above the ground is a function of time t is given by :

h= -4.9t^2 + 68.6t ...(1)

We need to find the maximum height of the model. First we find the time of max height using axis of symmetry of the equation as follows :

x=\dfrac{-b}{2a}

We have, a = -4.9 and b = 68.6

So,

t=\dfrac{-(68.6)}{2\times -4.9}\\\\=7\ s

Put t = 7 in equation (1)

h= -4.9(7)^2 + 68.6(7)\\\\=240.1\ m

So, the maximum height attained by the rocket is 240.1 m.

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