Neil tried to rewrite the expression 5^-6/5^-4
1 answer:
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Answer:
Step-by-step explanation:
Set up the equation:
Since C(t) gives the number of cars purchased in the t-th year after 1998, then make the number of cars equal to 15 000 and solve for t - the year:
20t^2 = 15000
t^2 = 750
t =
The year will be simply 1998 + 5 \sqrt{30}
Step-by-step explanation:
Given that the mean of the numbers is 12
so here
let's that one as x and another one as 2x since it is given that one is twice the other
Therefore we get
Given mean = 12
Hence it's 11 and 22
Answer:
The z-score for an income of $2,100 is 1.
Step-by-step explanation:
If X N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variate is known as the standard normal distribution.
Given:
µ = $2,000
σ = $100
<em>x</em> = $2,100
Compute the <em>z</em>-score for the raw score <em>x</em> = 2100 as follows:
Thus, the z-score for an income of $2,100 is 1.