The first way:
1. Reflect the figure I across the x-axis.
2. Translate the figure I and its reflection and rotate them 90 degrees.
The second way:
1. Reflect the figure I across the x-axis.
2. Rotate 90 degrees counterclockwise.
3. Rotate it across the y-axis.
Distance = rate*time, or
distance = (average speed)* time, so
average speed = distance/ time.
average speed = 205 mi / (3/12) h = 205 mi/ (1/4)h = 205*4 mi/h=
= 820 mi/h
It is looks to high for speed of the truck,
probably time should be 3.12 h,
then
average speed = 205 mi / (3.12) h ≈ 65.71 mi/h.
That looks close to real life.
The area, in square inches, outside the smaller region, but inside the larger region is 99π
<h3>How to determine the area, in square inches, outside the smaller region, but inside the larger region?</h3>
The given parameters are:
Radius, r1 = 1 inch
Radius, r2 = 10 inches
The area, in square inches, outside the smaller region, but inside the larger region is calculated as
Area = π(R^2 - r^2)
This gives
Area = π(10^2 - 1^2)
Evaluate the difference
Area = 99π
Hence, the area, in square inches, outside the smaller region, but inside the larger region is 99π
Read more about area at:
brainly.com/question/17335144
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25 were vanilla
500 divided by 100 is 5 meaning that one percent is 5 and 5x5 is 25
33 ÷ 3/4 = 33 × 4/3 = 44. The answer is solved by using this equation
