16+64=80 80*2=160
or it means
64/2=32 32+16= 48
or it means
64+16=80 80/2= 40
this is a horribly formatted question
Represent these consecutive numbers (assuming that they are all integers):
x
x+1
x+2
x+3
x+4
x+5
and so on
x+8
x+9 is the tenth number. x+9 = 10, so x = 9.
Think of it this way: there are 10 consecutive numbers, and the last one is 10.
Working backwards, we get the sequence 10, 9, ... 3, 2, 1.
The sum of such an arith sequence is equal to the count of the numbers times the average of the first and last terms:
sum here = 10(1+10)/2 = 5(11) = 55 (answer)
Answer:
9c+2
Step-by-step explanation:
Answer:
The answer is S(1,8)
Step-by-step explanation:
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First, plug in 5 for x:
| -5 * 5 + 12 | = |-25 + 12| = |-13|
Those two lines are absolute value, which measures the distance from the number to 0 on a number line. This distance is always positive.
The distance from -13 to 0 on a number line is 13. The answer is 13.
