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2 years ago

8

Benson played for 10 minutes after reaching home. He watched television for another 20 minutes before eating his lunch. His lunc

h, which lasted 20 minutes, was finished at 2:50pm. At what time did Benson reach home?

1 answer:

Goshia [24]2 years ago

7 0

Answer:

At 2:00.

Step-by-step explanation:

You take 10 minutes off 2:50 for play time add the two 20s together then subtract 40 to get 2:00.

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The variables y and x^2 are directly

choli [55]

Answer:

y = $\frac{20}{21}$ x²

Step-by-step explanation:

Given that y and x² are directly proportional then the equation relating them is

y = kx² ← k is the constant of proportion

When x = 2

y = k × 2² = 4k

When x = 5

y = k × 5² = 25k

Then

25k - 4k = 20 ( difference between values is 20 )

21k = 20 ( divide both sides by 21 )

k = $\frac{20}{21}$

y = $\frac{20}{21}$ x² ← equation of proportion

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2 years ago

500-400 x 1823= please help only Johannes02 comment

liberstina [14]

It is -728700 is my answer

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2 years ago

Read 2 more answers

Just need to know what x is haha

marishachu [46]

Answer: x=14

Step-by-step explanation:

The angles in a triangle are equal to 180 so

6x + 3 + 5x + x + 9 = 180

12x + 12 = 180

-12 -12

12x = 168

x = 14

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3 years ago

easy algebra question below first correct answer gets brainliest, if you put a link i will report and block

boyakko [2]

Answer:

6x²

Step-by-step explanation:

3x×2x=6...... then an x²

Therefore answer is 6x²

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2 years ago

Scientists have discovered a vaccine for a debilitating disease. This year there were 570,000 reported new cases of the disease

Ket [755]

Answer: There are approximately 853827 new cases in 6 years.

Step-by-step explanation:

Since we have given that

Initial population = 570000

Rate at which population decreases is given by

$\frac{2}{3}$

Now,

First year =570000

Second year is given by

$570000\times (\frac{1}{3})$

Third year is given by

$570000(\frac{1}{3})^2$

so, there is common ratio ,

it becomes geometric progression, as there is exponential decline.

so,

$570000,570000\times \frac{1}{3},570000\times( \frac{1}{3})^2,......,570000\times (\frac{1}{3})^6$

a=570000

common ratio is given by

$r=\frac{a_2}{a_1}=\frac{1}{3}$

number of terms = 6

Sum of terms will be given by

$S_n=\frac{a(1-r^n)}{(1-r)}$

We'll put this value in this formula,

$S_6=\frac{570000(1-(\frac{1}{3})^6}{(1-\frac{1}{3})}\\\\=853827.16$

So, there are approximately 853827 new cases in 6 years.

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2 years ago