Let 'c' represent the number of pictures Chelsea took.
Let 's' represent the number of pictures Sonya took.
For last year's Thanksgiving, c + s = 236
For this year's Thanksgiving, let 'x' represent the number of photos taken in total. x = c + s, where c and s are two integers that are the same (c = s).
And we know that for both years, c + s + x = 500.
As we know that c + s is already 236 from last year, we can remove c + s from the equation in bold and replace it with 236 instead.
236 + x = 500.
Now we have to isolate the x term.
x = 500 - 236
x = 264.
We know that x = c + s, where c and s are the same, so we can just use one of the variables and double it (so you either get 2c or 2s - it doesn't matter which one you pick because they're both the same).
2c = 264
c = 132
c = s
s = 132.
Both took 132 pictures this year.
Answer:
4,5,6 / 6,8,10 / 5,12,13 / ....
Step-by-step explanation:
Base on the pythagorean theorem, we have : a² + b² = c².
The first set : 4,5,6 - 4² + 5² = 6² (a possible set)
The second set : 6² + 8² = 10² (another possible set)
The last set : 5² + 12² = 13² (also possible)
There are a lot more sets, but I'll only list 3. Hope this helps :)
Answer:
81/10
Step-by-step explanation:
i just figured it out i really don't have one but i hope it helps
Answer:
33/10 and 55/15
Step-by-step explanation:
Possible denominators that are multiples of 5 less than 17 are 5, 10, 15.
Corresponding numerator ranges are [15, 20], [30, 40], and [45, 60]. In only two of these ranges are there any multiples of 11.
33 in [30, 40]
55 in [45, 60]
So, there are only two possible fractions meeting your requirement:
33/10 and 55/15
