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Ede4ka [16]
2 years ago
10

Solve the following system of equations for all three variables.

Mathematics
1 answer:
Semenov [28]2 years ago
5 0

Answer:

x=2, z=4, y=-6

Step-by-step explanation:

Add

<u>-9x-y+2z= -4</u>

<u>-6x+y+5z= 2</u>

-9x-6x is -15x

-y+y is 0

2z+5z is 7z

-4+2 is -2

So the equation now looks like this: -15x+7z=-2

Subtract

<u>-6x+y+5z= 2</u>

<u>-4x+y+5z= 6</u>

So the equation will look like this:

<u>-6x+y+5z= 2</u>

<u>-(-4x+y+5z= 6)</u>

-6x+4x is -2x

y-y is 0

5z-5z is 0

2-6 is -4

So the equation now looks like this: <u>-2x=-4</u>

You can find x by dividing -2 on both sides:

<u>x=2 </u>

So 2 is x

Now you can substitute x into 2

-15(2)+7z=-2

-30+7z=-2

7z=28

Divide 7 on both sides:

<u>z=4</u>

So now you can substitute z into 4 (For any of the three equation)

-4(2)+y+5(4)=6

-8+y+20=6

20 minus 8 is 12

y+12=6

Subtract 12 on both sides:

y=-6

So the answers are

x=2, z=4, y=-6

Hope this helps!

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