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sergij07 [2.7K]
3 years ago
14

You have just planted a new tree. To support the tree, you attach a wire from the trunk of th tree to a stake in the ground. Eac

h wire has a length of 7 feet. Suppose you put the stakes in the ground 5 feet from the base of the trunk. Approximately how far up the trunk should you attach the wires?
Mathematics
1 answer:
Tomtit [17]3 years ago
5 0

Answer: 4.9 ft

Step-by-step explanation:

Given

Length of wire l=7\ ft

Stake is at a distance of 5\ ft from the base of tree

suppose wire is attached y ft  above the base of tree

from the figure, we can write

\Rightarrow 7^2=5^2+y^2\\\Rightarrow y^2=49-25\\\Rightarrow y=\sqrt{24}\\\Rightarrow y=4.89\approx 4.9\ ft

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if MP =5.9, what is RN? round your answer to the nearest tenth. write NA if there is not enough information given. ​
ser-zykov [4K]

Answer:

1.8

Step-by-step explanation:

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Chelsea shows her work in finding the solution to 4x−5=2+3(x−3). After checking her answer in the original equation, she found t
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agrupe los términos semejantes: x=-7+5

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Step-by-step explanation:

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8 0
3 years ago
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kotykmax [81]
The answer will be 200 inches. 508 ÷ 2.54 = 200
4 0
3 years ago
Read 2 more answers
Match the term with the definition
katrin2010 [14]

Answer:

Plane: C) A flat surface that extends infinitively and has no depth; it has length and width

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I hope this helps

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3 0
3 years ago
What is the answer 2(4y+1)=3y
SCORPION-xisa [38]
2(4y+1) = 3y. We need to solve for y.
First let's get ride of the parenthesis by developing 2(4y+1). This means to multiply 2 by 4y and 2 by 1, and add them.
2(4y+1) = 2*4y + 2*1 = 8y + 2
So 2(4y+1)=3y
8y+2 = 3y
Then you subtract 8y from each side to have the variables on a side and the numbers on the other:
3y - 8y = 8y + 2 - 8y
-5y = 2
Then you divide each side by -5 to get the variable y alone on a side and its value on the other:
(-5y)/-5 = 2/-5
y = -2/5

You can re-check your answer (very important):
2(4y + 1) = 2(4*-2/5 + 1) = -1.2
3y = 3 * -2/5 = -1.2
So 2(4y+1)=3y= -1.2
The answer has been approved.

Hope this Helps! :)
4 0
4 years ago
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