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Yuki888 [10]
3 years ago
9

What is the least common denominator of 1/2, 2/3, and 3/4?A 48B 24C 16D 12​

Mathematics
1 answer:
nydimaria [60]3 years ago
8 0

Answer: D.) 12

Step-by-step explanation:

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The perimeter of a triangle is 133 inches. If one side of the triangle is five more than the shortest side, and the longest side
barxatty [35]

133=x + (x+5) + (x+14)

133 = 3x+19

3x=114

x= 114/3 =38

5+38 =43

38+14 =52

check: 38 +43 +52 = 133

3 sides are : 38, 43 & 52

8 0
3 years ago
If f(x) = x2 – 2x, find:<br> f(-3) = [?]
maksim [4K]

9514 1404 393

Answer:

  15

Step-by-step explanation:

Put the value where the variable is and do the arithmetic.

  f(-3) = (-3)² -2(-3) = 9 +6

  f(-3) = 15

3 0
3 years ago
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Find the perimeter. Simplify your answer.<br> 4y-5<br> 10y-4<br> 7y+8<br> 74-5
KonstantinChe [14]

(10y - 4) + (7y + 8) + (7y - 5) + (4y - 5) =

= 10y - 4 + 7y + 8 + 7y - 5 + 4y - 5 =

= 10y + 7y + 7y + 4y - 4 + 8 - 5 - 5 = <u>2</u><u>8</u><u>y</u><u> </u><u>-</u><u> </u><u>6</u>

6 0
3 years ago
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Find the sum. 2/5 + 1/2​
dybincka [34]
2/5 + 1/2

4+5 / 10 • look for the LCD of 5 and 2
which is 10 then 5 goes 2
times into 10 the multiply by 2
= 4. Then 2 goes 5 times into
10 then multiply by 1 = 5.

Therefore the sum of 2/5 + 1/2 =9/10
5 0
3 years ago
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A box of pencils is 5 1/4 inches wide. Seven pencils, laid side by side, take up 2 5/8 inches of the width. How many inches of t
Andre45 [30]

Answer:   Width of box is not taken up by pencils =  2\dfrac58\text{ inches}

Width of each pencil =\dfrac38\text{ inches}

Step-by-step explanation:

Given: Width of pencil box = 5\dfrac14\text{ inches}=\dfrac{21}{4}\text{ inches}

Width of seven pencils = 2\dfrac58\text{ inches}=\dfrac{16+5}{8}\text{ inches}=\dfrac{21}{8}\text{ inches}

Width of box is not taken up by pencils =  Width of pencil box  - Width of seven pencils

\left \{ {{y=2} \atop {x=2}} \right. \dfrac{21}{4}-\dfrac{21}{8}\\\\=\dfrac{21\times2-21}{8}\\\\=\dfrac{21}{8}\text{ inches}=2\dfrac58\text{ inches}

Width of box is not taken up by pencils =  2\dfrac58\text{ inches}

Width of each pencil = (Width of seven pencils ) ÷ 7

=\dfrac{21}{8}\div7\\\\=\dfrac{21}{8}\times\dfrac17\\\\=\dfrac38\text{ inches}

Width of each pencil =\dfrac38\text{ inches}

3 0
3 years ago
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