The answer would be JG.
If we rotate triangle PMO so that the 6 cm side is on the bottom, it would look more similar to the triangle JGH, and make it clear that side PM corresponds to side JG
Answer:
Solve for A by simplifying both sides of the equation, then isolating the variable.
A
=
45
−
B
4
Step-by-step explanation:
<span>When you are sampling from a small finite lot, the hypergeometric distribution applies. The binomial is a poor approximation in this case.
The general equation for the hypergeometric where aCx means the number of combinations of a items selected x at-a-time.:
P(x) =[(aCx)(N-aCn-x)]/NCn
Where
N is the lot size = 20
a is the number of defectives in the lot = 3.
x is the number of defectives in the sample.
n is the sample size = 2.
A. The probability that the first item is defective is
P(x=1) = [(3C1)(17C1)]/(20C2)
= (3)(17)/190 = 0.268
The probability that the second item is defective is
P(x = 1) = [(2C1)(17C1)]/(19C2) = (2)(17)/171 = 0.199.
So the total probability is (0.268)(0.199) = 0.0532
B. The probability that the first item is good is:
P(x = 0) = (3C0)(16C2)]/20C2 = (1)(120)/190 = 0.632
The probability that the second item is defective is
P(x = 0) =[(3C0)(16C2)]/19C2
= (1)(120)/171 = 0.670.
The total probability is 0.632(0.670) = 0.4234</span>
Answer:
f6h40
Step-by-step explanation:
Step 1 :
h23
Simplify ———
f3
Equation at the end of step 1 :
h23
((f9) • ———) • h17
f3
Step 2 :
Multiplying exponential expressions :
2.1 h23 multiplied by h17 = h(23 + 17) = h40
Final result :
f6h40
<span>Because <span>t <span>is given in years and 1.08 <span>= <span>1 <span>+ <span>0.08, the annual percent increase
<span>is 8%.
To find the monthly percent increase that gives an 8% annual increase,
<span>use the fact that
t =
<span><span><span><span>
<span><span><span><span>and the properties of exponents to rewrite the
model in a form that reveals the monthly growth rate.</span></span></span>
</span></span></span></span></span></span></span></span></span></span></span></span></span></span>
