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Ivanshal [37]
2 years ago
12

What unit should be placed on a volume answer? cubed or squared

Mathematics
2 answers:
Jobisdone [24]2 years ago
8 0
The unit placed on a volume answer is cubed and area is squared
Mrrafil [7]2 years ago
4 0

Answer:

volume is cubed

area is squared

Step-by-step explanation:

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You are designing the garden of your dream and you are going to start with a blank canvas. That means killing everything before
Aleks [24]

Answer:

2.5 bottles or 3 bottles

Step-by-step explanation:

Given that :

Dimension of lot :

22.5 yds by 20.4 yds

Area of lot = 22.5 * 20.4 = 459 yd²

Volume per bottle of herbicide = 12 fl oz

1.1 fl oz combined with water treats an area of 155 ft²

Number of 1.1 fl oz from 12 fl oz that can be obtained : 12 / 1.1 = 10.90

1 yard² = 9 feet²

459 yard² = (459 * 9) = 4131 feet²

Number of 151 feet² that can be obtained from 4131 feet²

4131 feet² / 155 ft²

= 27.3576 times

= 27.3576 / 10.909

= 2.507

This means he'll have to buy a minimum of 3 bottles if a fraction of a bottle can't be purchased.

7 0
3 years ago
The first angle of a triangle is 4 times the number of degrees in the second angle. The third angle of the triangle is 12 degree
xenn [34]

Answer:

1st angle: 128°

2nd angle: 32°

3rd angle: 20°

Step-by-step explanation:

You can start by setting up an equation. 180=x+4x+x-12. It sould all add up to 180 because angles of a triangle always add up to 180, and x represents the second triangle (you use the second angle as x because the other two angles elaborate off of this second angle).  Then you solve. Add 12 to 180 and get 192. Then you can add like terms and make it 192=6x (you add the x's together). Lastly divide 192 by 6 and get 32. So the measurement of angle 2 is 32°. Then you multiply 32 by 4 to get the 1st angle measure, being 128. Lastly subtract 12 from 32 and get 20 for angle three. To check you work add the three angle measures you got and see if they =180, if so then you are correct.

5 0
2 years ago
Can anybody write an equation for the following word story:
Rudiy27
40=6.95c+5.25
The $40 is what you want it all to equal, so that goes to one side by itself.
The CDs are 6.95 each, so they get a variable to show that.
The 5.95 is added to that, showing that it's only charged once.
Then, all you have to do is solve for c, which is the number of CD's you can buy.
4 0
3 years ago
For x, y ∈ R we write x ∼ y if x − y is an integer. a) Show that ∼ is an equivalence relation on R. b) Show that the set [0, 1)
vodomira [7]

Answer:

A. It is an equivalence relation on R

B. In fact, the set [0,1) is a set of representatives

Step-by-step explanation:

A. The definition of an equivalence relation demands 3 things:

  • The relation being reflexive (∀a∈R, a∼a)
  • The relation being symmetric (∀a,b∈R, a∼b⇒b∼a)
  • The relation being transitive (∀a,b,c∈R, a∼b^b∼c⇒a∼c)

And the relation ∼ fills every condition.

∼ is Reflexive:

Let a ∈ R

it´s known that a-a=0 and because 0 is an integer

a∼a, ∀a ∈ R.

∼ is Reflexive by definition

∼ is Symmetric:

Let a,b ∈ R and suppose a∼b

a∼b ⇒ a-b=k, k ∈ Z

b-a=-k, -k ∈ Z

b∼a, ∀a,b ∈ R

∼ is Symmetric by definition

∼ is Transitive:

Let a,b,c ∈ R and suppose a∼b and b∼c

a-b=k and b-c=l, with k,l ∈ Z

(a-b)+(b-c)=k+l

a-c=k+l with k+l ∈ Z

a∼c, ∀a,b,c ∈ R

∼ is Transitive by definition

We´ve shown that ∼ is an equivalence relation on R.

B. Now we have to show that there´s a bijection from [0,1) to the set of all equivalence classes (C) in the relation ∼.

Let F: [0,1) ⇒ C a function that goes as follows: F(x)=[x] where [x] is the class of x.

Now we have to prove that this function F is injective (∀x,y∈[0,1), F(x)=F(y) ⇒ x=y) and surjective (∀b∈C, Exist x such that F(x)=b):

F is injective:

let x,y ∈ [0,1) and suppose F(x)=F(y)

[x]=[y]

x ∈ [y]

x-y=k, k ∈ Z

x=k+y

because x,y ∈ [0,1), then k must be 0. If it isn´t, then x ∉ [0,1) and then we would have a contradiction

x=y, ∀x,y ∈ [0,1)

F is injective by definition

F is surjective:

Let b ∈ R, let´s find x such as x ∈ [0,1) and F(x)=[b]

Let c=║b║, in other words the whole part of b (c ∈ Z)

Set r as b-c (let r be the decimal part of b)

r=b-c and r ∈ [0,1)

Let´s show that r∼b

r=b-c ⇒ c=b-r and because c ∈ Z

r∼b

[r]=[b]

F(r)=[b]

∼ is surjective

Then F maps [0,1) into C, i.e [0,1) is a set of representatives for the set of the equivalence classes.

4 0
2 years ago
I need know what 18 divided by 9.63 equals
pshichka [43]
The answer is 1.869 or 1.87
6 0
3 years ago
Read 2 more answers
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