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3 years ago

Which set of data shows the least variability?

Mathematics

1 answer:

juin [17]3 years ago

5 0

B. Shows lest Variability.
A) is constant, C) is Constant, D) is constant but with and addition of 20 and remaining

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You have a solid Rectangle of dough. Consider the cross sections that are formed when you slice into the cube as described. Draw

Phantasy [73]

B is the answer I think trying it tho

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2 years ago

A child pool is 3.8 feet wide 5.5 feet long and 1.2 fee deep, what is the volume of the pool?

Anni [7]

Answer:

25.08

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

I am greater than 4 tens and less than 5 tens I have 9 ones

aliina [53]

4 tens = 40 and 5 tens = 50 … therefore the number has to be between 40 and 50

So: 40 < x <50 … this says that x is greater than 40 and less than 50

So the possible numbers would be: 41,42,43,44,45,46,47,48,49

Now the number must have 9 ones … which mean the only number would be 49

4 0

3 years ago

70=(4x+36)/2 figure this out please

adell [148]

Answer:

$\boxed{\bold{\huge{\boxed{x = 26}}}}$

Step-by-step explanation:

$70 = \frac{4x+36}{2}$

Multiplying both sides by 2

$70 * 2 = 4x+36$

$140 = 4x+36$

Subtracting 36 to both sides

$140 - 36 = 4x$

$104 = 4x$

Dividing both sides by 4

$26 = x$

$x = 26$

3 0

3 years ago

Read 2 more answers

in a five character password the first two characters must be digits and the last three characters must be letters if no charact

Vilka [71]

Answer:

1,404,000 unique passwords are possible.

Step-by-step explanation:

The order in which the letters and the digits are is important(AB is a different password than BA), which means that the permutations formula is used to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

$P_{(n,x)} = \frac{n!}{(n-x)!}$

In this question:

2 digits from a set of 10(there are 10 possible digits, 0-9).

3 characters from a set of 26. So

$P_{10,2}P_{26,3} = \frac{10!}{8!} \times \frac{26!}{23!} = 10*9*26*25*24 = 1404000$

1,404,000 unique passwords are possible.

5 0

3 years ago