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ratelena [41]
3 years ago
15

Which set of data shows the least variability?

Mathematics
1 answer:
juin [17]3 years ago
5 0
B. Shows lest Variability.
A) is constant, C) is Constant, D) is constant but with and addition of 20 and remaining
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2,230

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What is 7.2 times 10^5 equal to.
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The answer to this is 720000
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I drove to my parents' house at 60 miles per hour. if i had driven 50 miles an hour instead, then i would have gotten there 40 m
Fittoniya [83]
Use distance = rate x time

Let "t" be the time it took for you to drive to your parent's house at 60mph.

So 60t would be the distance.

And "t+40" would be the time it took for you to get to your parent's house at 50 mph.  And that total distance would be 50(t+40).

Since both the distances are the same, this gives us the equation:

60t = 50(t+40)

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Driving at 60 mph for 200 minutes equates to a total distance of 200 miles.
5 0
3 years ago
A researcher compares the effectiveness of two different instructional methods for teaching physiology. A sample of 178 students
xxTIMURxx [149]

Answer:

critical value = 1.645

The 90% confidence interval = ( -22.62, -17.58)

Step-by-step explanation:

Given that:

the sample  size n_1 = 178

the sample size n_2 = 226

the sample mean \overline x_1 = 54.4

the sample mean \overline x_2 = 74.5

population standard deviation \sigma_1 = 18.58

population standard deviation \sigma_2 = 9.52

level of significance ∝ = 1 - 0.90 = 0.10

The critical value for Z_{\alpha/2} = Z _{0.10/2} = Z_{0.005} is 1.645

For the construction of our confidence interval, we use 90% since that is used to find the critical value.

∴

The margin of error = Z \times\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}

1.645 \times\sqrt{\dfrac{18.58^2}{178} + \dfrac{9.52^2}{226}}

1.645 \times\sqrt{\dfrac{345.2164}{178} + \dfrac{90.6304}{226}}

1.645 \times\sqrt{2.34042}

\simeq 2.52

The lower limit = ( \overline x_1 - \overline x_2) - (M.O.E)

= ( 54.4-74.5) - (2.52)

= -20.1 - 2.52

= -22.62

The upper limit = ( \overline x_1 - \overline x_2) + (M.O.E)

= ( 54.4-74.5) + (2.52)

= -20.1 + 2.52

= -17.58

The 90% confidence interval = ( -22.62, -17.58)

6 0
3 years ago
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