Which set of data shows the least variability?
1 answer:
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Answer:
BD = <u>1</u> unit
AD = <u>1</u> unit
AB = <u>1.6</u> units
AC = <u>1.6</u> units
Step-by-step explanation:
In the picture attached, the triangle ABC is shown.
Given that triangle ABC is isosceles, then ∠B = ∠C
∠A + ∠B + ∠C = 180°
36° + 2∠B = 180°
∠B = (180° - 36°)/2
∠B = ∠C = 72°
From Law of Sines:
sin(∠A)/BC = sin(∠B)/AC = sin(∠C)/AB
(Remember that BC is 1 unit long)
AB = AC = sin(72°)/sin(36°) = 1.6
In triangle ABD, ∠B = 72°/2 = 36°, then:
∠A + ∠B + ∠D = 180°
36° + 36° + ∠D = 180°
∠D = 180° - 36° - 36° = 108°
From Law of Sines:
sin(∠A)/BD = sin(∠B)/AD = sin(∠D)/AB
(now ∠A = ∠B)
BD = AD = sin(∠A)*AB/sin(∠D)
BD = AD = sin(36°)*1.6/sin(108°) = 1
The equation y = x + 8 uses the slope intercept form
Remember that the slope intercept formula is:
y = mx + b
m is the slope
b is the y-intercept
In this case
y = 1x + 8
m = 1
y = x + 8
b = 8 OR y-intercept of this line is (0, 8)
You can plot the point (0, 8) on a graph. Then to find the next point you will rise up 1 and over right 1 (this is the slope). You can find another point after that by going down one and left one from the point (0, 8)
The graph should look like the one in the image below
Hope this helped! Let me know if you have any further questions
~Just a girl in love with Shawn Mendes
The volume of the region R bounded by the x-axis is:
If the axis of revolution is the boundary of the plane region and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.
From the given graph:
The given straight line passes through two points (0,0) and (2,8). Thus, the equation of the straight line becomes:
here:
- (x₁, y₁) and (x₂, y₂) are two points on the straight line
Suppose we assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8) from the graph, we have:
y = 4x
Now, our region bounded by the three lines are:
- y = 0
- x = 2
- y = 4x
Similarly, the change in polar coordinates is:
- x = rcosθ,
- y = rsinθ
where;
- x² + y² = r² and dA = rdrdθ
Therefore;
- rsinθ = 0 i.e. r = 0 or θ = 0
- rcosθ = 2 i.e. r = 2/cosθ
- rsinθ = 4(rcosθ) ⇒ tan θ = 4; θ = tan⁻¹ (4)
- ⇒ r = 0 to r = 2/cosθ
- θ = 0 to θ = tan⁻¹ (4)
Then:
Learn more about the determining the volume of solids bounded by region R here:
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