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3 years ago

Find the missing side length

Mathematics

1 answer:

lidiya [134]3 years ago

7 0

Answer:

The length of the missing side is

$4 \sqrt{5} \\ if \: you \: want \: it \: not \: simplified \: it \: would \: be \: \\ \sqrt{80}$

Step-by-step explanation:

You could do Pythagorean theorem which is:

${a}^{2} + {b}^{2} = {c}^{2} \\ {8}^{2} + {4}^{2} = {c}^{2} \\{64} + {16} = {c}^{2} \\ \sqrt{80} = {c}^{2} \\ 4\sqrt{5} = c$

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The answer is Letter B - $2,850.

Multiply the number of shares to their respective costs per share. Add the results. Get the total number of shares then divide it by 10 before multiplying the result to 4.25. Add the product to the previous total.

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4 years ago

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Answer:

Step-by-step explanation:

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4 years ago

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Step-by-step explanation:

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3 years ago

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Examine the required sample size needed to be able to

Xelga [282]

Answer:

$n=(\frac{2.33(500)}{10})^2 =13572.25 \approx 13573$

And if we use a sample level of n =2000 the margin of error would be higher as we can see here:

$ME=2.33\frac{500}{\sqrt{2000}}=26.05$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=500$ represent the population standard deviation assumed

n represent the sample size (variable of interest)

Confidence =98% or 0.98

ME = 10 represent the margin of error desired

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =10 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.01;0;1)", and we got $z_{\alpha/2}=2.33$ , replacing into formula (b) we got:

$n=(\frac{2.33(500)}{10})^2 =13572.25 \approx 13573$

So the answer for this case would be n=13573 rounded up to the nearest integer

And if we use a sample level of n =2000 the margin of error would be higher as we can see here:

$ME=2.33\frac{500}{\sqrt{2000}}=26.05$

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4 years ago

How many solutions does the following system of equations have?<br> v=3x +2<br> 2v=5x+8

Alja [10]

Answer:

The answer is C, zero solutions.

Step-by-step explanation:

y = 5/2x + 2

2y = 5x + 8

Multiply 2 to the first equation.

2y = 5x + 4

Compare it with the other equation

2y = 5x + 4

2y = 5x + 8

Cancel 2y and 5x on both sides.

Remaining:

4 = 8

4 ≠ 8. Therefore, the answer is C, zero solutions.

4 0

4 years ago

Find the missing side length ​

Find the missing side length