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djyliett [7]
3 years ago
7

A high speed train travels at a speed of 300km/h. if the train sets off from a station A at 13 44 and reaches station B at 15 12

. Find the distance between two stations, giving your answer in km​
Mathematics
1 answer:
Masja [62]3 years ago
5 0

Answer:

See below.

Step-by-step explanation:

The train leaves station A at 13:44 and arrives at station B at 15:12.

Which means the train took 1 hour and 28 minutes to arrive at station B.

The train travels at 300 km/h. It took at least one hour, so the answer > 300 km.

Now, the remaining 28 minutes. We divide them by 60, as there’s 60 minutes in one hour and multiply by 300, as that’s how fast the train travels per hour.

28/60*300 = 140.

300 + 140 = 440.

The distance between the stations is 440 km.

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jeka94

Answer:

A) 27

Step-by-step explanation:

\frac{16}{16 + 12}  =  \frac{63 - ?}{63}

➡️ \frac{4}{7}  =  \frac{63-? }{63}

➡️ 63 - ? = 36

➡️ ? = 27

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If f(x)=3x-2 and g(x)=x^2+1, find f(g(-1)) and g(f(3))
julsineya [31]

Answer:

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Step-by-step explanation:

We know the definition of both functions: f(x)=3x-2, and g(x)=x^2+1

A) In order to evaluate what f(g(-1)) is, let's first investigate what g(-1) is using the definition for this function:

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Now let's find what f(2) is using f(x) definition: f(x)=3x-2\\f(2)=3(2)-2\\f(2)=6-2\\f(2)=4

B) In order to evaluate what g(f(3)) is, let's first investigate what f(3) is using the definition for this function:

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Now let's find what g(7) is using the definition for this function:

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nata0808 [166]

Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

\boxed{\text{2. 4.7 units}}

Step-by-step explanation:

Assume your triangle has the dimensions shown below.

Before we can use the Law of Sines, we must find ∠C.

1. Calculate ∠C

\begin{array}{rcl}A + B + C & = & 180^{\circ}\\66^{\circ} + 76^{\circ} + C & = & 180^{\circ}\\142^{\circ} + C & = & 180^{\circ}\\C & = & 38\, ^{\circ}\\\end{array}

2. Calculate b

Use the Law of Sines

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