A garph y=2 represents a line parallel to the x axis with the y coordinate equal to 2.
The point which lies on the y=2 graph has its y coordinate equal to 2.
In the given options, (3,2) is the coordinate with the y coordinate equal to 2.
Hence, (3,2) lies on the graph of y = 2.
Option (D) is the answer.
Answer:
A.
= Cube root of 4.
Step-by-step explanation:
We have been given an expression
. We are asked to find the equivalent expression for our given expression.
Using exponent property
, we will get,
![2^{\frac{2}{3}}=\sqrt[3]{2^2}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B2%5E2%7D)
![2^{\frac{2}{3}}=\sqrt[3]{4}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B4%7D)
Upon looking at our given choices, we can see that option A is the correct choice.
The completely factored expression of 2x^2 + 4x + 3xy + 6y is (2x + 3y)(x + 2)
<h3>How to factor the polynomial?</h3>
The expression is given as:
2x^2 + 4x + 3xy + 6y
Group the expression into two
[2x^2 + 4x] + [3xy + 6y]
Factor out each group
2x(x + 2) + 3y(x + 2)
Factor out x + 2
(2x + 3y)(x + 2)
Hence, the completely factored expression of 2x^2 + 4x + 3xy + 6y is (2x + 3y)(x + 2)
Read more about factored expression at:
brainly.com/question/723406
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Answer:
the coefficients of static friction is 0.577
the coefficients of fkinetic friction is 0.54
Step-by-step explanation:
given information
θ = 30°
S = 2.5 m
t = 4 s
- Static friction
F - F(friction) = 0
W sin θ = μs W cos θ
μs = sin θ/ cosθ
= tan θ
= tan 30°
= 0.577
- kinetic friction
S =
+ 
= 0
S = 
a =
= 
= 0.3 
F - F(friction) = m a
W sin θ - μ W cos θ = m a
mg sin θ - μk mg cos θ = m a
g sin θ - μk g cos θ = a
μk = g sin θ - a / g cos θ
= 9.8 sin 30° - 0.3 / 9.8 cos 30°
= 0.54
You gotta fond the radius of the circle
I’m pretty sure