Step-by-step explanation:





<u>Let us assume that:</u>

<u>Therefore, the equation becomes:</u>






<u>Now substitute the value of u. We get:</u>


<u>Therefore:</u>


★ <u>Which is our required answer.</u>

(a + b)² = a² + 2ab + b²
(a - b)² = a² - 2ab + b²
a² - b² = (a + b)(a - b)
(a + b)³ = a³ + 3ab(a + b) + b³
(a - b)³ = a³ - 3ab(a - b) - b³
a³ + b³ = (a + b)(a² - ab + b²)
a³ - b³ = (a - b)(a² + ab + b²)
(x + a)(x + b) = x² + (a + b)x + ab
(x + a)(x - b) = x² + (a - b)x - ab
(x - a)(x + b) = x² - (a - b)x - ab
(x - a)(x - b) = x² - (a + b)x + ab
Hello from MrBillDoesMath!
Answer:
See Discussion section below
Discussion:
2x^2 + 5x + 3 = (2x+3)(x+1) which is Choice 3
3x^2+10x+4 =-1/3 (-3 x + sqrt(13) - 5) (3 x + sqrt(13) + 5)
I don't think any of the provided choices are right!
8x^2+10x-3 = (2x+3)(4x-1) which is Choice 2
6x^2-7x-4 = -1/24 (-12 x + sqrt(145) + 7) (12 x + sqrt(145) - 7)
I don't think any of the provided choices are right!
2x^2+x-28 = (2x-7)(x+4) which is Choice 2
Thank you,
MrB
It should represent Sydney's age, right? The equation would be 3s-5 I'm 99% sure lol
A) w + 7 = L
B) w * L = 120
A) w = L -7 then substituting this into B)
(L-7) * L = 120
L² -7L = 120
L² -7L -120 = 0
Solving by quadratic Formula:
L1 = 15
L2 = -8
If length = 15, then width = 8