Answer: The loser's card shows 6.
Explanation: Let's start by naming the first student A and the second student B.
Since the product of A and B are either 12, 15, or 18, let's list every single possibility, the first number being A's number and the second number being B's number.
1 12
1 15
1 18
2 6
2 9
3 4
3 5
3 6
4 3
5 3
6 2
6 3
9 2
12 1
15 1
18 1
Now, the information says that A doesn't know what B has, so we can immediately cross off all of the combinations that have the integer appearing once and once ONLY off, because if it happened once only, A would know of it straight away. Now, our sample space becomes much smaller.
1 12
1 15
1 18
2 6
2 9
3 4
3 5
3 6
6 2
6 3
Using this same logic, we know that we can cross off all of the digits that occur only once in B's column.
2 6
3 6
Now, A definitely knows what number B has because there is only one number left in B. Hence, we can conclude that the loser, B, has the integer 6.
Do you have any pictures?
Answer: There are 32 students who like brussels sprouts but dislike beans.
Step-by-step explanation:
Since we have given that
Number of students eat in the cafeteria = 120
Fraction dislike lime beans = 
Fraction who dislike lime beans and brussles sprouts both = 
Fraction who dislikes lime beans but not brussles is given by
So, Number of students who like brussels sprouts but dislike lima beans is given by
Hence, there are 32 students who like brussels sprouts but dislike beans.
Multiply 2/1 or 2 on both sides to get "y" by itself
y ≤ -14
