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AveGali [126]
3 years ago
10

The polygons in each pair are similar. find the missing side length

Mathematics
1 answer:
Orlov [11]3 years ago
5 0

Answer:

Can you add a picture?

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X, Y and Z form the vertices of a triangle. XY = 12.4m, XZ = 10.4m and YZ = 8.7m. Find the angle ∠ YXZ rounded to 1 DP.
sweet-ann [11.9K]

Answer:

43.8°

Step-by-step explanation:

Applying,

Cosine rule,

From the diagram attached,

x² = y²+z²-2yxcos∅.................... Equation 1

where ∅ = ∠YXZ

Given: x = 8.7 m, y = 10.4 m, z = 12.4 m

Substitute these values  into equation 1

8.7² = 10.4²+12.4²-[2×10.4×12.4cos∅]

75.69 = (108.16+153.76)-(257.92cos∅)

75.69 = 261.92-257.92cos∅

collect like terms

257.92cos∅ = 261.92-75.69

257.92cos∅ = 186.23

Divide both sides by the coefficient of cos∅

cos∅ = 186.23/257.92

cos∅ = 0.722

Find the cos⁻¹ of both side.

∅ = cos⁻¹(0.7220)

∅ = 43.78°

∅ = 43.8°

6 0
3 years ago
1.2 repeating as a fraction
Step2247 [10]
11/9 is what im thinking
3 0
3 years ago
Please help asap i will mark branlist If correct
Alja [10]

Answer:

B is the only one that goes through the axis

3 0
4 years ago
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You want to find the volume of the solid obtained by rotating about the x-axis the region under the curve y = x 1 / 6 y=x1/6 fro
Natasha2012 [34]

Answer:

Area = πr², where "r" is some distance "y" and/or the function "(1/6)x"; depending on the situation

Step-by-step explanation:

If I'm picturing this correctly, you'll have conical shape after revolving the function about the x-axis. If you took some generic slice and wanted to find the area of the resulting cross-section, then you would have a circle whose radius is some arbitrary value of the line that matches the slice.

For example:

y = (1/6)x right?

If you took a slice at x = 2, then the radius of the resulting cross-sectional circle would be equal to y = (1/6)•2 =1/3.

From here you just plug it into the area of a circle, πr², to get an area of π/3.

Except with an integral you need to take all the points on the interval, so the radius comes out to be the function itself.

Assuming your integral is in terms of dx, r=y. But in order to integrate in terms of dx you must replace "y" with its function (1/6)x. So ultimately r=(1/6)x and Area = π(1/6)x.

4 0
3 years ago
Try one on your own! Find the midpoint of
valkas [14]
I don’t really know BAT ST Y S(
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