All categories

3 years ago

A recipe calls for 8 ounces of butter and 3 otnces of chocolate. If I reduce the

Mathematics

2 answers:

LuckyWell [14K]3 years ago

6 0

Answer:

you should use 1 ounce of chocolate to 6 ounces of butter

Step-by-step explanation:

if you are going from 8 ounces to 6 ounces of butter you are subtracting 2 ounces. to even it out you should use two ounces less of chocolate, leaving 1 ounce of chocolate to be used

katrin2010 [14]3 years ago

6 0

1 oz of chocolate
—————————

You might be interested in

Write the following number in standard form plezz<br><br> 7.6 x 10^3

blondinia [14]

10^3=1,000

Anything multiplied by 1 is that number. In this case, multiply 7.6 by 1, then add 3 zeroes.

---

hope it helps

7 0

3 years ago

Read 2 more answers

Find log 1985 to four decimal places.

PolarNik [594]

Answer:

Your answer is 3.2977

Hope that this is helpful. Tap the crown button, Like & Follow me

5 0

3 years ago

Consider the quadratic equation. x^2=4x-5. How many solutions does the equation have?

Vesna [10]

x^2=4x-5
subtract 4x from both sides
x^2-4x=-5
add 5 to both sides
x^2-4x+5=0

input into quadratic formula which is x= $\frac{-b+ \sqrt{b^2-4ac} }{2a}$ or $\frac{-b- \sqrt{b^2-4ac} }{2a}$

si ax^2+bx+c
so a=1
b=-4
c=5
input
$\frac{-(-4)+ \sqrt{-4^2-4(1)(5)} }{2(1)}$ = $\frac{4+ \sqrt{16-20} }{2(1)}$ = $\frac{4+ \sqrt{-4} }{2}$ = $\frac{4+ \sqrt{4} times \sqrt{-1} }{2}$ $\frac{4+2 times \sqrt{-1} }{2}= \frac{6 times \sqrt{-1} }{2}=3 times \sqrt{-1} [\tex][\tex]\sqrt{-1}$ representeds by 'i' so solution is 3i

then if other way around then wyou would do
$\frac{-(-4)- \sqrt{-4^2-4(1)(5)} }{2(1)}$ = $\frac{4- \sqrt{16-20} }{2(1)}= \frac{4- \sqrt{-4} }{2} =\frac{4- \sqrt{4} times \sqrt{-1} }{2}= \frac{4-2 times \sqrt{-1} }{2}=\frac{2 \sqrt{-1} }{2}= \sqrt{-1}$ and [\tex]\sqrt{-1} [/tex] is represented by i

the solution is x=3i or i (i= $\sqrt{-1}$ )
but i is not real, it is imaginary so there are no real solution so the answer is C

3 0

3 years ago

What are the square roots of -8-6i?<br>Thanks!

ira [324]

Answer:

1-3i

Step-by-step explanation:

√ -8-6i = 1-3i

(1-3i) x (1-3i) = -8-6i

6 0

3 years ago

A marketing researcher wants to estimate the mean savings ($) realized by shoppers who showroom. Showrooming is the practice of

PSYCHO15rus [73]

Answer:

a) $58-1.984\frac{55}{\sqrt{100}}=47.087$

$58+1.984\frac{55}{\sqrt{100}}=68.913$

So on this case the 95% confidence interval would be given by (47.087;68.913)

b) The confience interval calculated from part a is in order to estimate the true mean of savings. And we can extrapolate the results obtained for this new sample size:

$47.087 < \mu < 68.913$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=100-1=9$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,99)".And we see that $t_{\alpha/2}=1.984$

Now we have everything in order to replace into formula (1):

$58-1.984\frac{55}{\sqrt{100}}=47.087$

$58+1.984\frac{55}{\sqrt{100}}=68.913$

So on this case the 95% confidence interval would be given by (47.087;68.913)

Part b

The confience interval calculated from part a is in order to estimate the true mean of savings . And we can extrapolate the results obtained for this new sample size:

$47.087 < \mu < 68.913$

6 0

3 years ago