Answer:
Rider 1 does one round in 15 min, and will complete another in each consecutive multiple of 15 min
Rider 2 does one round in 18 min, and will complete another in each consecutive multiple of 18 min
Assuming that they start together, they will complete another round together in a time that is both multiples of 15min and 18 min.
Then we need to find the smallest common multiple between 15 and 18.
To smallest common multiple between two numbers, a and b, is equal to:
a*b/(greatest common factor between a and b).
Now, the greatest common factor between 15 and 18 can be found if we write those numbers as a product of prime numbers, such as:
15 = 3*5
18 = 2*3*3
The greatest common factor is 3.
Then the smallest common multiple will be:
(15*18)/3 = 90
This means that after 90 mins, they will meet again at the starting place.
Answer:
y=65x
Step-by-step explanation:
x represents the # of hours
Answer:
The answer should be m < -2.5
Step-by-step explanation:
I was taught this before and my teacher always said if its a open circle then its > or < if its a closed circle then it should have the line under it, and the line is going down so it would be Less than sign
Using the Pythagoras theorem
15^2 = x^2 + h^2 where h = height of ladder on the nuiding
h^2 = 15^2 - 6^2 = 189
= 13.75 ft to nearest hundredth
Linear, because the points (1,8) (2,6) (3,4) etc are decreasing at a constant rate of -2.
