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Artyom0805 [142]
3 years ago
12

Which graph represents the arithmetic sequence 8 6 4 2 0

Mathematics
2 answers:
Nataliya [291]3 years ago
7 0
Linear, because the points (1,8) (2,6) (3,4) etc are decreasing at a constant rate of -2.
jeka943 years ago
6 0
So, we decrease by 2 each time
and we start at 8

y=-2x+10 is the equation
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PLEASE ANSWER
marissa [1.9K]

Answer:

The answer Is I think 40

6 0
3 years ago
(2p+4)+5(p-1)-(p+7)<br><img src="https://tex.z-dn.net/?f=%282p%20%2B%204%29%20%2B%205%28p%20-%201%29%20-%20%28p%20%2B%207%29" id
mylen [45]

(2p+4)+5(p-1)-(p+7)\\ \\ 2p+4+5p-5-(p+7)\\ \\ 2p+4+5p-5-p-7\\ \\ (2p+5p-p)+4-5-7\\ \\ (7p-p)-1-7\\ \\ 6p-8=2(3p-4)

That should be the final answer. If you need help with the distribution process I can explain that separately if needed. If not, hope this helps!

6 0
3 years ago
Read 2 more answers
The solid below is made from 1 yard cubes. Find its surface area.
xxMikexx [17]

Answer:

Surface area = 80yd

Step-by-step explanation:

4x3 + 4x4 + 4x3 + 4x4 + 4x3 + 4x3 = 80

hope this helped :D

7 0
3 years ago
The number n of people using the elevator in an office building every hour is given by n = t2 − 10t + 40. In this equation, t is
Morgarella [4.7K]

Answer:

The number of persons using the elevator at any hour is never going to be less that 15.

Step-by-step explanation:

To solves this you have to suppose that there are at least 15 persons on the elevator, and the equation is converted into an inequation:  

t^2-10t+40

Now you transform the inequation back to an equation to solve it:

t^2-10t+25=0

You need to know if there is any negative solution for the equation, to do this you can use the discriminant for a quadratic equation:

D=b^2-4ac

In this case, you have a=1, b=-10, c=25

D= (-10)^2-4(1)(25)\\D=0

Since the discriminant is 0 and a<0 the equation always is going to be positive. Therefore, the number of persons using the elevator at any hour is never going to be less than 15.

6 0
4 years ago
HELP PLS ILL GIVE BRAINLIEST
Vilka [71]

Answer:

2•5s+s

10s+s

11s

the first one

8 0
2 years ago
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