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zavuch27 [327]
2 years ago
14

Find the area of the kite.

Mathematics
2 answers:
stich3 [128]2 years ago
4 0

Answer:

18m I guess

Step-by-step explanation:

babunello [35]2 years ago
3 0

Answer:

18 m

Step-by-step explanation:

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1 point
sergey [27]

Answer:

the answer is 97 student tickets and 15 adult tickets

Step-by-step explanation:

4 0
2 years ago
For which of the following is x=-5 a soulution? select all that apply​
victus00 [196]

Answer:

The answer are B and C

Step-by-step explanation:

-5² + 50 = 25

 |2 x 5| = 10

6 0
3 years ago
Read 2 more answers
Please help me with this trigonometry question:
zzz [600]

Answer:

The distance from A to B is 736.2 to the nearest tenth foot

Step-by-step explanation:

In ΔCAB

∵ m∠CAD = 30° ⇒ exterior angle of Δ at vertex A

∴ m∠CAD = m∠ACB + m∠ABC

∵ m∠ABC = 20°

∴ m∠ACB = 30° - 20° = 10°

We will use the sin rule to find the distance AB

∵ \frac{sin20}{1450}=\frac{sin10}{AB}

∴ AB=\frac{1450(sin10)}{sin20}=736.1842936 ≅ 736.2 to the nearest tenth foot

8 0
3 years ago
24 is 16% of what number
Eva8 [605]
Is/of = %/100 plug the numbers in 24/x = 16/100 then cross multiply then you get 2400 = 16x so you get x by itself so you would have to divide by 16. 2400/16 = 16x/16 the 16 on the x side cancel out so you get x = 150 (I used proportions)
8 0
3 years ago
Read 2 more answers
Can I get help solving this graph please?
Daniel [21]
see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100)  B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40)  C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0)  B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60)  C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then 
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x) 
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then 
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x) 
h'(x)=18/25=0.72 

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0
3 years ago
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