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How do you find the percent of an equation??

vlabodo [156]

<span>15 is 10% what number? in equation form is 15/10% = X.We need to first convert the percentage to an equivalent decimal to do our calculation.<span>Converting a percentage to a decimal we remove the percentage sign and divide by 100.</span></span>

3 0

3 years ago

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What is the simplified form of the following expression 7(^3√2x)-3(^3√16x)-3(^3√8x)

svlad2 [7]

Answer:

The simplified form of the expression is $\sqrt[3]{2x}-6\sqrt[3]{x}$

Step-by-step explanation:

Given : Expression $7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}$

To Simplified : The expression

Solution :

Step 1 - Write the expression

$7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}$

Step 2- Simplify the roots and re-write as

$16=2^3\times2$ and $8=2^3$

$7\sqrt[3]{2x}-3\times2\sqrt[3]{2x}-3\times2\sqrt[3]{x}$

Step 3- Solve the multiplication

$7\sqrt[3]{2x}-6\sqrt[3]{2x}-6\sqrt[3]{x}$

Step 4- Taking $\sqrt[3]{2x}$ common from first two terms

$\sqrt[3]{2x}(7-6)-6\sqrt[3]{x}$

$\sqrt[3]{2x}-6\sqrt[3]{x}$

Therefore, The simplified form of the expression is $\sqrt[3]{2x}-6\sqrt[3]{x}$

5 0

3 years ago

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Slope of 9 passes through the point (-3,2)

boyakko [2]

Answer:

y-2=9(x+3)

Step-by-step explanation:

y-y1=m(x-x1)

y-2=9(x-(-3))

y-2=9(x+3)

7 0

3 years ago

A small plane took 3 hours to fly 960 km from Ottawa to Halifax with a tail wind. On the return trip, flying into the wind, the

Rina8888 [55]

Answer:

Wind speed: $\rm 40\; km \cdot h^{-1}$ .
Speed of the plane in still air: $\rm 320\; km \cdot h^{-1}$ .

Step-by-step explanation:

This problem involves two unknowns:

wind speed, and
speed of the plane in still air.

Let the speed of the wind be $x \rm \; km \cdot h^{-1}$ , and the speed of the plane in still air be $y\rm \; km \cdot h^{-1}$ . It takes at least two equations to find the exact solutions to a system of two variables.

Information in this question gives two equations:

It takes the plane three hours to travel $\rm 960\; km$ from Ottawa to with a tail wind (that is: at a ground speed of $x + y$ .)
It takes the plane four hours to travel $\rm 960\; km$ from Halifax back to Ottawa while flying into the wind (that is: at a ground speed of $-x + y$ .)

Create a two-by-two system out of these two equations:

$\left\{ \begin{aligned}&3(x + y) = 960 && (1) \\ &4(-x + y) = 960 && (2) \end{aligned}\right.$ .

There can be many ways to solve this system. The approach below avoids multiplying large numbers as much as possible.

Note that this system is equivalent to

$\left\{ \begin{aligned}&4 \times 3 (x + y) = 4\times960 && 4 \times (1) \\ &3\times 4(-x + y) = 3\times 960 && 3 \times (2) \end{aligned}\right.$ .

$\left\{ \begin{aligned}&12 x + 12y = 4\times960 && 4 \times (1) \\ &- 12x + 12y = 3\times 960 && 3 \times (2) \end{aligned}\right.$ .

Either adding or subtracting the two equations will eliminate one of the variables. However, subtracting them gives only $1 \times 960$ on the right-hand side. In comparison, adding them will give $7 \times 960$ , which is much more complex to evaluate. Subtracting the second equation ( $3 \times (2)$ ) from the first ( $4 \times (1)$ ) will give the equation