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3 years ago

Priya has a recipe for banana bread. She uses

Mathematics

2 answers:

mr_godi [17]3 years ago

4 0

Answer:

(3/2)f

it doesn't really show me a good copy of the question but I hope you found this helpful

Arturiano [62]3 years ago

4 0

Yep I agree with the person

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POINTS UP FOR GRABS TAKE IT QUICK

stealth61 [152]

Answer:

omg

Step-by-step explanation:

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3 years ago

Read 2 more answers

n considering the cross YyRr x YyRr, the phenotype ratios of the F2 generation will be _____. 1:3:1 3:1 9:3:3:1 4:1

Marrrta [24]

The cross of YyRr will produce 16 distinct genotypes.

If the two alleles are far enough on the same chromosome, then the Y and R alleles will be distributed independently of one another, so that the genotypic ratio among each allele would be 1:2:1 (YY:Yy:yy, and similarly for the R allele). Then the dihybrid cross will yield a genotypic ratio of 1:2:1:2:4:2:1:2:1 (YYRR:YYRr:YYrr:YyRR:YyRr:Yyrr:yyRR:yyRr:yyrr).

Now, assuming perfect Mendelian inheritance (complete dominance), the phenotypes exhibited by YY and Yy will be considered equivalent, and similarly for RR and Rr, so the phenotypic ratio would be 9:3:3:1 (YR:Yr:yR:yr).

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3 years ago

Write 6,020,300 in expanded form.

dangina [55]

Answer:

Step-by-step explanatio

6,000,000 + 20,000 + 300

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3 years ago

Someone please ill mark you the brainliest! No cheating or else i’ll report you.

lukranit [14]

Answer:

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3 years ago

If the distance from A (5,6) to B (1, b) is twice the distance from B to

Nimfa-mama [501]

Answer:

The possible values of $b$ are -2.944 and -9.055, respectively.

Step-by-step explanation:

From statement we know that $AB = 2\cdot BC$ . By Analytical Geometry, we use the equation of a line segment, which is an application of the Pythagorean Theorem:

$AB = 2\cdot BC$

$\sqrt{(x_{B}-x_{A})^{2}+(y_{B}-y_{A})^{2}} = 2\cdot \sqrt{(x_{C}-x_{B})^{2}+(y_{C}-y_{B})^{2}}$ (1)

Where:

$x_{A}$ , $x_{B}$ , $x_{C}$ - x-Coordinates of points A, B and C.

$y_{A}, y_{B}, y_{C}$ - y-Coordinates of points A, B and C.

$(x_{B}-x_{A})^{2}+(y_{B}-y_{A})^{2} = 4\cdot (x_{C}-x_{B})^{2}+4\cdot (y_{C}-y_{B})^{2}$

Then, we expand and simplify the expression above:

$x_{B}^{2}-2\cdot x_{A}\cdot x_{B} +x_{A}^{2} +y_{B}^{2}-2\cdot y_{A}\cdot y_{B} + y_{A}^{2} = 4\cdot (x_{C}^{2}-2\cdot x_{C}\cdot x_{B}+x_{B}^{2})+4\cdot (y_{C}^{2}-2\cdot y_{C}\cdot y_{B}+y_{B}^{2})$

$x_{B}^{2}-2\cdot x_{A}\cdot x_{B} + x_{A}^{2} +y_{B}^{2}-2\cdot y_{A}\cdot y_{B} + y_{A}^{2} = 4\cdot x_{A}^{2}-8\cdot x_{C}\cdot x_{B}+4\cdot x_{B}^{2}+4\cdot y_{C}^{2}-8\cdot y_{C}\cdot y_{B}+4\cdot y_{B}^{2}$

If we know that $x_{A} = 5$ , $y_{A} = 6$ , $x_{B} = 1$ , $y_{B} = b$ , $x_{C} = 1$ and $y_{C} = -3$ , then we have the following expression:

$1 -10 +25 +b^{2} -12\cdot b+36 = 100 -8 +4 +36+24\cdot b +4\cdot b^{2}$

$b^{2}-12\cdot b +52 = 4\cdot b^{2}+24\cdot b +132$

$3\cdot b^{2}+36\cdot b +80 = 0$

This is a second order polynomial, which means the existence of two possible real solutions. By Quadratic Formula, we have the following y-coordinates for point B:

$b_{1} \approx -2.944$ , $b_{2} \approx -9.055$

In consequence, the possible values of $b$ are -2.944 and -9.055, respectively.

8 0

3 years ago