Answer:
(-b±√(b²-4ac))/(2a)
where,
ax²+bx+c=0
a, b, c = constants, where a ≠ 0
x = the unknown
Step-by-step explanation:
Average = mean = sum of the values / number of data
Values = h, j, and k
Number of data = 3
Sum of the values = h + j + k
Mean = [h + j + k] / 3
=> Answer: option c. [h+j+k] over 3
Answer:
A. 
Step-by-step explanation:
So to get the area of a square, we need to find the length of one side.
We know the length of the larger square is a, so the area of the larger cube is 
We can find the length of a side of the smaller square by using pythagoreans theorem to find the hypotenuse of the triangle formed in the bottom left corner. The length of one side along the x axis is a - b, and the length of the other side, along the y-axis, is b.
We can plug it into pythagoreans theorem to get
(C represents the length of one side of the smaller square, and the hypotenuse of the triangle)

The area of the smaller triangle is C squared to the area of the smaller triangle is

To get the ratio of the smaller square in comparison to the larger square we divide the area of the smaller square by the area of the larger square.
So the ratio should be

74746394738284729274638292
(1,2)(4,-1)
slope = (y2 - y1) / (x2 - x1)
slope = (-1 - 2) / (4 - 1) = -3/3 = -1
the slope is -1......I am not sure of the mistake.....unless she just added (-1 - 2) and got 3 instead of -3.......or when dividing -3/3....she maybe forgot about the negative sign