Solve 4e^1+3x-9e^5-2x=0
1 answer:
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Answer:
Let X the random variable who represents the file sizeof music. We know the following info:
We select a sample of n=50 nails. That represent the sample size.
Since the sample size is large enough n >30, we can use the central limit theorem. From this theorem we know that the distribution for the sample mean is given by:
And we can approximate the distribution of the sample mean as a normal distribution and no matter if the distribution for X is right skewed or no.
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".
Let X the random variable who represents the file sizeof music. We know the following info:
We select a sample of n=50 nails. That represent the sample size.
Since the sample size is large enough n >30, we can use the central limit theorem. From this theorem we know that the distribution for the sample mean is given by:
And we can approximate the distribution of the sample mean as a normal distribution and no matter if the distribution for X is right skewed or no.
Answer:
The value of test statistics is 1.06.
Step-by-step explanation:
We are given that according to a marketing research study, American teenagers watched 14.8 hours of social media posts per month last year, on average. A random sample of 11 American teenagers was surveyed and the mean amount of time per month each teenager watched social media posts was 15.6. This data has a sample standard deviation of 2.5.
We have to test if the mean amount of time American teenagers watch social media posts per month is greater than the mean amount of time last year or not.
Let, NULL HYPOTHESIS, :
= 14.8 hours {means that the mean amount of time American teenagers watch social media posts per month is same as the mean amount of time last year}
ALTERNATE HYPOTHESIS, :
> 14.8 hours {means that the mean amount of time American teenagers watch social media posts per month is greater than the mean amount of time last year}
The test statistics that will be used here is One-sample t-test;
T.S. = ~
where, = sample mean amount of time per month each teenager watched social media posts = 15.6 hours
= sample standard deviation = 2.5 hours
n = sample of teenagers = 11
So, <u>test statistics</u> = ~
= 1.06
Hence, the value of test statistics is 1.06.