By using cross mutliplication, there are 24 gallons in the water tank after 30 minutes.
<h3>How to estimate the filling time of a water tank by cross multiplication</h3>
According to the statement the water tank is full at constant rate, 10 % tank capacity per each 5 minutes. The tank has a capacity of 40 gallons. The gained capacity is determined by the following cross multiplication, where the water capacity is directly proportional to filling time:
x ∝ t
x = (n / 100) · V × (T / t) (1)
Where:
- n - Initial capacity percentage of the water tank, in percentage.
- V - Full capacity of the water tank, in gallons.
- T - Final time, in minutes.
- t - Initial time, in minutes.
x = [0.1 · (40 gal)] × (30 min / 5 min)
x = 24 gal
There are 24 gallons in the water tank after 30 minutes.
To learn more on cross multiplication: brainly.com/question/15209325
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A) can be done using u-substitution .... Let u = x^2, du = 2x dx
C) can be done using trig identity ... cos(2x) = 1 - 2sin^2
B) can only be done using integration by parts. It is a product of 2 distinct functions and a u-sub does not simplify the integral.
Answer:
-1000
Step-by-step explanation:
take -10 x -10 x -10= -1000:)
Answer:
C. x-axis: temperature in increments of 5; y-axis: minutes in increments of 1
Step-by-step explanation:
