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3 years ago

13

A person is running a distance race at a constant rate. What time will they finish the race what information would you need to b

e able to solve the problem?

2 answers:

Shtirlitz [24]3 years ago

4 0

Answer:

you need the distance

Step-by-step explanation:

Zinaida [17]3 years ago

3 0

Answer:

you need the distance they're running and the pace they are running at.

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13 points plus brainliest to the correct answer!

TEA [102]

The equation of a straight line is given by:

y = mx + c

where m is the slope and c is the y-intercept.

From the given graph, the y-intercept is 1.

The slope of a straight line is given by:

$m= \frac{y_2-y_1}{x_2-x_1}$

Where $(x_1,y_1)$ and $(x_2,y_2)$ are two points on the line.

From the graph, (0, 1) and (14, 8) are two points on the line, thus:

$m= \frac{8-1}{14-0} = \frac{7}{14} = \frac{1}{2}$

Therefore, the equation representing the graph is $y= \frac{1}{2} x+1$

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3 years ago

Read 2 more answers

How do u round decimals like 18.194 rounded to the nearest hundred

Lilit [14]

You look at the decimal place next to the hundredth one. In this case, it’s 4 so you round down
18.19 is the answer

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3 years ago

How do you simplify 2+-2<img src="https://tex.z-dn.net/?f=%5Csqrt%7B6%7D" id="TexFormula1" title="\sqrt{6}" alt="\sqrt{6}" align

ehidna [41]

1+(put the little sign)6

that should be the answer, good luck.

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3 years ago

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

so

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

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3 years ago

12 yd<br> 4 yd<br> 7 yd<br> 7yd<br> 4yd<br> 4 yd<br> 4 yd<br> 4 yd<br> what is the area

N76 [4]

I think the answer to it is 2,688

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3 years ago