Triangle ABC and triangle DCE are congruent, so line DE = line AB
Use the cosine rule to find angle ACB






Angle ACB = 48.1°
Answer:
zzz
Step-by-step explanation:
DEEEZZZ
Answer:
i think there was a typo bc u didnt put the number of zoo animals
Step-by-step explanation:
Y = -4x + 2
3x + 2y = 6 (or in y-intercept form y=-3/2x + 3)
2x - y = 7 equals y = 2x -7 in y-intercept form. This means that the line has a positive slope and therefore goes upwards. This cannot be a potential equation because the line shown is clearly pointing downwards.
y=5 indicates that the line is a horizontal line that neither points upwards or downwards. This cannot be a potential equation because the line is pointing downwards.
The only possible equations left are y= -4x + 2 and 3x + 2y = 6, both of which graph a line pointing downwards because their slopes are negative. Hope this helps!
Answer:
a≈2.343
Step-by-step explanation:
View Image
Integrating an equation from boundary x₀ to x₁ gives you the area underneath that boundary.
So to find the boundary that split the equation into 2 equal areas, the boundary must lie somewhere between the 2 place to want to split up. In other word, <em>a</em> is the end boundaries of the first integral and the starting boundary of the second integral.
Since the two area must equal to each other, set the two integral equal to each other and solve for a.