The domain of a function is the set of all possible x-values which will make the function “work”, and will output real
y-values
Answer:
multiply length with breadth which is 34 *42
I can conclude that the sign of the other integer is positive and that the other integer is 6 or greater.
I tried explaining it, but failed miserably. I'm so sorry! :(
Answer:
The center of the circle is
![(-\frac{3}{2},2)](https://tex.z-dn.net/?f=%28-%5Cfrac%7B3%7D%7B2%7D%2C2%29)
Step-by-step explanation:
Let the equation of the circle be
, where (-a,-b) is the center of this circle.
The points lying the circle must satisfy the equation of this circle.
A(0,0)
We substitute this point to get;
![0^2+0^2+2a(0)+2b(0)+c=0](https://tex.z-dn.net/?f=0%5E2%2B0%5E2%2B2a%280%29%2B2b%280%29%2Bc%3D0)
![\implies c=0](https://tex.z-dn.net/?f=%5Cimplies%20c%3D0)
B(-3,0)
![(-3)^2+0^2+2a(-3)+2b(0)+c=0](https://tex.z-dn.net/?f=%28-3%29%5E2%2B0%5E2%2B2a%28-3%29%2B2b%280%29%2Bc%3D0)
![\implies 9+0-6a+0+c=0](https://tex.z-dn.net/?f=%5Cimplies%209%2B0-6a%2B0%2Bc%3D0)
![\implies -6a+c=-9](https://tex.z-dn.net/?f=%5Cimplies%20-6a%2Bc%3D-9)
But c=0
![\implies -6a=-9](https://tex.z-dn.net/?f=%5Cimplies%20-6a%3D-9)
![\implies a=\frac{3}{2}](https://tex.z-dn.net/?f=%5Cimplies%20a%3D%5Cfrac%7B3%7D%7B2%7D)
C(1,2)
![1^2+2^2+2a(1)+2b(2)+c=0](https://tex.z-dn.net/?f=1%5E2%2B2%5E2%2B2a%281%29%2B2b%282%29%2Bc%3D0)
![1+4+2a+4b+c=0](https://tex.z-dn.net/?f=1%2B4%2B2a%2B4b%2Bc%3D0)
![2a+4b+c=-5](https://tex.z-dn.net/?f=2a%2B4b%2Bc%3D-5)
Put the value of 'a' and 'c' to find 'b'
![2(\frac{3}{2})+4b+0=-5](https://tex.z-dn.net/?f=2%28%5Cfrac%7B3%7D%7B2%7D%29%2B4b%2B0%3D-5)
![3+4b+0=-5](https://tex.z-dn.net/?f=3%2B4b%2B0%3D-5)
![4b=-5-3](https://tex.z-dn.net/?f=4b%3D-5-3)
![4b=-8](https://tex.z-dn.net/?f=4b%3D-8)
b=-2
Hence the center of the circle is
![(-\frac{3}{2},2)](https://tex.z-dn.net/?f=%28-%5Cfrac%7B3%7D%7B2%7D%2C2%29)