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3 years ago

A school track is shown.

Mathematics

2 answers:

aliina [53]3 years ago

8 0

Answer:

Hey There!

Given that:

There are 2 semicircles of the same radius i.e a circle

and a Rectangle

To find:

The perimeter i.e the sum of the circumference of the circle + the perimeter of the rectangle

<h2> $\huge\colorbox{pink}{s}olution = >$ </h2><h2>2πr + 2(l+w)</h2>

where

π =3 .14
r=74/2=37m
l= 1000m
w= 74m

ella [17]3 years ago

4 0

Answer:

2232.36m

Explanation:

since the perimeter of two semicircles adds up to that of one circle, the perimeter of the track would be the perimeter of the circle + the length of the rectangle.

we can find the perimeter of the circle using the formula of π × diameter, which would be:

π × diameter

= 3.14 × 74

= 232.36

now, we can add this to the given length of the rectangle:

232.36 + 1000 + 1000 = 2232.36

thus, the perimeter of the track is 2232.36m.

i hope this helps! :D

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sveta [45]

Part A:
y=mx+b
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2 years ago

A student of the author earned grades of 92, 83, 77, 84, and 82 on herfive regular tests. She earned grades of 88 on the final e

goblinko [34]

The class is weighted as follows:

60% Regular Tests

10% Final Exam

15% Project

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The total weighted points possible for the class are as follows:

(100+100+100+100+100)*.6 + 100*.1 + 100*.15 + 100*.15 = 340

To calculate her individual final weighted grade we plug in her scores for each category and complete the following computation:

(92+83+77+84+82)*.6 + 88*.1 + 95*.15 + 77*.15 = 285.4

So her weighted grade percent would be 285.4/340 = 83.9% which is a B.

8 0

3 years ago

to build the garden of your dreams you need 11 m^3 of coil containing 46% clay. you have two types of soil you can combine to ac

aivan3 [116]

Answer: 9m^3 of soil with 50% clay and 2m^3 of soil with 28% clay is required

Step-by-step explanation:

Let x represent the quantity of the soil containing 50% clay that you would use.

Let y represent the quantity of the soil containing 28% clay that you would use.

To build the garden of your dreams you need 11 m^3 of soil.

x + y = 11 - - - - - - - - -1

Since the soil must contain 46% clay, the total amount of clay required is 46/100 × 11 = 5.06 m^3.

you have two types of soil you can combine to achieve this: soil with 50% clay and soil with 28% clay. This means that the quantity of both soils required to achieve 5.06 m^3 will be

0.5x + 0.28y = 5.06 - - - - - - - -2

Substituting x = 11 - y into equation 1, it becomes

0.5(11 - y) + 0.28y = 5.06

5.5 - 0.5y + 0.28y = 5.06

- 0.5y + 0.28y = 5.06 - 5.5

- 0.22y = - 0.44

y = - 0.44/ -0.22 = 2

Substituting y = 2 into x = 11 - y, it becomes

x = 11 - 2 = 9

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3 years ago

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lyudmila [28]

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Step-by-step explanation:

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