Question

A school track is shown.

Answer 1

Answer:

Hey There!

Given that:

There are 2 semicircles of the same radius i.e a circle

and a Rectangle

To find:

The perimeter i.e the sum of the circumference of the circle + the perimeter of the rectangle

$\huge\colorbox{pink}{s}olution = >$

2πr + 2(l+w)

where

• π =3 .14
• r=74/2=37m
• l= 1000m
• w= 74m

=>

2 x 3.14 x 37 + 2(1000+74)

=>232.36 +2148

=>2,380.36 m

Answer 2

Answer:

2232.36m

Explanation:

since the perimeter of two semicircles adds up to that of one circle, the perimeter of the track would be the perimeter of the circle + the length of the rectangle.

we can find the perimeter of the circle using the formula of π × diameter, which would be:

π × diameter

= 3.14 × 74

= 232.36

now, we can add this to the given length of the rectangle:

232.36 + 1000 + 1000 = 2232.36

thus, the perimeter of the track is 2232.36m.

i hope this helps! :D