So
1/2x+2=2/3x
convert to common fraction
1/2=3/6
2/3=4/6
3/6x+2=4/6x
subtract 3/6x from both sides
2=1/6x
multiply boh tisdes by 6
12=x
the tank can hold 12 gallon
Answer:
Where is the function shown below?
Step-by-step explanation:
Answer:
<h2>14mph</h2>
Step-by-step explanation:
Given the gas mileage for a certain vehicle modeled by the equation m=−0.05x²+3.5x−49 where x is the speed of the vehicle in mph. In order to determine the speed(s) at which the car gets 9 mpg, we will substitute the value of m = 9 into the modeled equation and calculate x as shown;
m = −0.05x²+3.5x−49
when m= 9
9 = −0.05x²+3.5x−49
−0.05x²+3.5x−49 = 9
0.05x²-3.5x+49 = -9
Multiplying through by 100
5x²+350x−4900 = 900
Dividing through by 5;
x²+70x−980 = 180
x²+70x−980 - 180 = 0
x²+70x−1160 = 0
Using the general formula to get x;
a = 1, b = 70, c = -1160
x = -70±√70²-4(1)(-1160)/2
x = -70±√4900+4640)/2
x = -70±(√4900+4640)/2
x = -70±√9540/2
x = -70±97.7/2
x = -70+97.7/2
x = 27.7/2
x = 13.85mph
x ≈ 14 mph
Hence, the speed(s) at which the car gets 9 mpg to the nearest mph is 14mph
Answer:
Angle 9: 60°
Angle 10: 30°
Side = radius = 40sqrt(x/3)
Area = [800sqrt(3)]x
Step-by-step explanation:
Total angle in a hexagon:
(6 - 2) × 180
720
Each interior angle:
720/6 = 120
angle 9 = 120/2 = 60
Angle 10 = 60/2 = 30
sin(60) = 20sqrt(x)/r
r = 20sqrt(x) ÷ sqrt(3)/2
r = 40sqrt(x/3)
Side:
sin(30) = ½s/(40sqrt(x/3))
½s = 20sqrt(x/3)
s = 40sqrt(x/3)
Area = (3sqrt(3))/2 × s²
Area = 3sqrt(3)/2 × 1600x/3
Area = [800sqrt(3)]x