R(t) = integral of r'(t) = integral of ti + e^tj + te^tk = 1/2t^2i + e^tj + (te^t - e^t)k + c
r(0) = j - k + c = i + j + k
c = i + 2k
Therefore, r(t) = (1/2t^2 + 1)i + e^tj + (te^t - e^t + 2)k
1) 2.92• 10^-3 2) 2.16•10^7. 3)7.5•10^8
- The 20th percentile represent the temperature value which is less than or equal to the 20% of the temperature values in the distribution.
- The 20th percentile temperature is 36.5°C which is Mr. Whitney's temperature.
- The mean temperature value in °Fahrenheit is 98.249°F
- The standard deviation value of temperature in °F is 32.734°F
The 20th percentile represents the score at which less than or equal to 20% of the scores in a distribution may be found. This is the score at which less than or equal to 20% of the temperature values in the distribution may be found.
Mr. Whitney's temperature :
20th percentile ;
20% of (n)
Where n = count of temperature values = 130
20% × 130 = 26th term
The 26th falls in 36.5 temperature value.
The mean temperature reading in degree Fahrenheit :
°F = (9/5)°C + 32
Mean in °C = 36.805
°F = (9/5) × 36.805 + 32
°F = 66.249 + 32
= 98.249°F
The standard deviation of temperature reading in degree Fahrenheit :
°F = (9/5)°C + 32
Standard deviation in °C = 0.408
°F = (9/5) × 0.408 + 32
°F = 0.7344 + 32
= 32.7344°F
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Answer:
70%
Step-by-step explanation:
60% chance of math homework, thus 40% of no homework
70% chance of english homework, thus 30% of no homework
Chance that there is no homework in math OR english
= 40% + 30% = 70%
Answer:
n = 7
a = 10 m
r = 10.3826 m
R = 11.5238 m
A = 363.391 m2
P = 70 m
x = 128.571 °
y = 51.4286 °
