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Morgarella [4.7K]
2 years ago
15

If AABC is reflected across the y-axis, what are the coordinates of A'?

Mathematics
1 answer:
mrs_skeptik [129]2 years ago
4 0

Answer: (-2, -5)

Step-by-step explanation:

When reflecting over the y axis, (x, y) becomes (-x, y).

So A(2, -5) turns into (-2, -5).

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Answer:

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Step-by-step explanation:

Substitute the value of x to the 2nd equation

3(2y-4)-6y=-12

6y-12-6y=-12

0=0

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Phantasy [73]

Step-by-step explanation:

r = \sqrt{ \frac{ax - p}{q + bx} } \\  {r}^{2}  =  \frac{ax - p}{q + bx}

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x =  \frac{q {r}^{2}  + p}{a - b {r}^{2} }

7 0
3 years ago
Read 2 more answers
Write the standard equation of a circle with center (-2,5) and the point (4,13) on the circle ​
n200080 [17]

since the point (4,13) is on the circle, then the distance from the center to it, is the radius of the circle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{13})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{[4-(-2)]^2+[13-5]^2}\implies r=\sqrt{(4+2)^2+(13-5)^2} \\\\\\ r=\sqrt{36+64}\implies r=\sqrt{100}\implies r=10 \\\\[-0.35em] ~\dotfill

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-2}{ h},\stackrel{5}{ k})\qquad \qquad radius=\stackrel{10}{ r}\\[2em] [x-(-2)]^2+[y-5]^2=10^2\implies (x+2)^2+(y-5)^2=100

6 0
3 years ago
HURRY BRAINLIEST AND 40 POINTS!!!
poizon [28]

Answer:

Option 3

Step-by-step explanation:

3 × (-4 - n/-2) 《 5

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8 0
3 years ago
A gallon of gasoline costs $2.96. Your car has a 25-gallon gas tank and can travel 28.8 miles on each gallon of gasoline. You ta
Andreas93 [3]

Answer:

$70.56

Step-by-step explanation:

Lets convert the mixed number (trip length) to decimal.

We know 3/5 (by long division) is 0.6, so 705  3/5th = 705.60 miles

Now, let's come to the problem:

1 gallon = 28.8 miles (mileage)

or

$2.96 = 28.8 miles

To find cost per mile, we divide:

\frac{2.96}{28.8}=0.10

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Since we want to travel 705.60 miles, we multiply to find the cost:

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6 0
4 years ago
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