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ziro4ka [17]
3 years ago
15

Find the volume of this square pyramid

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
5 0

Answer:

216

Step-by-step explanation:

Svet_ta [14]3 years ago
4 0

Answer:

72yd

Step-by-step explanation:

Hope that helps

hsobsnsjns

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2 1/2x + 1/4 + 3/4x = 1/8
Vinil7 [7]

\frac{5}{2}x+\frac{1}{4}  +\frac{3}{4} x=\frac{1}{8} \\\\\frac{5}{2}(8)x+\frac{1}{4}  (8)+\frac{3}{4}(8) x=\frac{1}{8}(8)\\20x+2+6x=1\\20x+6x=1-2\\26x=-1\\\frac{26x}{26} =\frac{-1}{26} \\x=-\frac{1}{26}

6 0
1 year ago
The manager at the local auto shop has found that the probability that a car brought into the shop requires an oil change is 0.8
Ber [7]

Answer:

0.85

Step-by-step explanation:

Given two events A and B, the probability that either A or B occurs is given by:

p(A\cup B) = p(A)+p(B)-p(A\cap B)

where

p(A) the probability that A occurs

p(B) is the probability that B occurs

p(A\cap B) is the probability that both A and B occur at the  same time

In this problem, we know the following facts:

p(o) = 0.83 is the probability that the car requires an oil change

p(b)=0.17 is the probability that the car requires a brake repair

p(o\cap b) = 0.15 is the probability that the car requires both an oil change and brake repair

Therefore, the probability that either o (car requiring oil change) or b (car requiring brake repait) occur is:

p(o\cup b)=p(o)+p(b)-p(o\cap b)=0.83+0.17-0.15 = 0.85

4 0
3 years ago
An=−2+32(n−1)<br><br> What is the 21st term of the sequence?
OLEGan [10]

Answer:

a₂₁ = 638

Step-by-step explanation:

substitute n = 21 into the explicit formula

a₂₁ = - 2 + 32(21 - 1) = - 2 + 32(20) = - 2 + 640 = 638

5 0
2 years ago
I need help pls i would really appreciate it !!
vlabodo [156]
Answer : a
Sin is opposite/hypotenuse which is 8/10
And this is 4/5
3 0
3 years ago
Read 2 more answers
Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi
ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles  carry just one person.    

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

\mu = np = 92(0.64) = 58.88

\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60

We have to evaluate the probability that more than 47 cars carry just one person.

P(x \geq 47)

After continuity correction, we will evaluate

P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)

= 1 - P(z \leq -2.6913)

Calculation the value from standard normal z table, we have,  

P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0
3 years ago
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