You cannot solve this equation, because you have no y or x values. However, you can change the equation to equal x.
1. -10/9
2. 2/5
3. -2/5
4. 3/5
5. 1/10
6. -10/3
1. To solve this problem, it is important to know that<span> the logarithmic functions and the exponential functions are inverse. Then, you have:
</span><span>
e^a=28.37
</span><span> a=ln(28.37)
</span><span>
2. Therefore: </span><span>Which logarithmic equation is equivalent to the exponential equation e^a=28.37? A</span><span>s you can see, the answer for this question is:
</span><span>
a=ln(28.37)</span>
Answer:
The first set of consecutive even integers equals (8 , 6)
The second set is ( - 8 and - 6) which also works.
Step-by-step explanation:
Equation
(x)^2 + (x + 2)^2 = (x)(x + 2) + 52 Remove the brackets on both sides
Solution
x^2 + x^2 + 4x + 4 = x^2 + 2x + 52 Collect the like terms on the left
2x^2+ 4x+ 4 = x^2 + 2x + 52 Subtract right side from left
2x^2 - x^2 + 4x - 2x + 4 - 52 = 0 Collect the like terms
x^2 + 2x - 48 = 0 Factor
(x + 8)(x - 6) = 0
Answer
Try the one you know works.
x - 6 = 0
x = 6
Therefore the two integers are 6 and 8
6^2 + 8^2 = 100
6*8 + 52 = 100
So 6 and 8 is one set of consecutive even numbers that works.
========================
What about the other set.
x + 8 = 0
x = - 8
x and x + 2
- 8 and -8 + 2 = - 8, - 6
(- 8 )^2 + (- 6)^2 = 100
(-8)(-6) + 52 = 100
Both sets of consecutive numbers work.
So,
10% is also known as one-tenth.
If 5 is one-tenth of something, that means that we can multiply 5 by 10 to get ten-tenths of that something.
5 * 10 = 50
The number is 50.
