3 years ago

What is the zero for 2x2-7=4

2 answers:

6 0

2x^2-7=4
subtract 4 from both sdies
2x^2-11=0
therefor
2x^2=11
divide by 2
x^2=5.5
square root both sdies
x=-2.345 or 2.345

3 0

2x² - 7 = 4
 +7 +7
 2x² = 11
 2 2
 x² = 5 1/2
 x = √5 1/2

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