What is the zero for 2x2-7=4
2 answers:
2x^2-7=4
subtract 4 from both sdies
2x^2-11=0
therefor
2x^2=11
divide by 2
x^2=5.5
square root both sdies
x=-2.345 or 2.345
2x² - 7 = 4
<u> +7 +7</u>
<u>2x²</u> = <u>11</u>
2 2
x² = 5 1/2
x = √5 1/2
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D, 49.42
Step-by-step explanation:
ΔVFT=180-90-43=47
formula
a/sin A = b/sin B/ = c/sin C
So,
FV/sin90=53/sin47
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