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ddd [48]
2 years ago
15

Help neededdddddddddddd

Mathematics
1 answer:
antoniya [11.8K]2 years ago
4 0

Answer:

SU = 30

RS = 27 I believe

Step-by-step explanation:

Hope that helps!

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I’m kinda confused. Can someone help.
horsena [70]

Answer:

PQ = PM\cos MPQ + MQ\cos MQP=2PM\cos MQP

Step-by-step explanation:

given MQR = 60, PQR = 75

MQP = 75 -60= 15QR = ((18(1+\cos 30))^{2}-(2\cos 15)^{2})^{\frac{1}{2}}

WE KNOW THAT MQR +QRM +QMR = 180

MPQ = MQP AS ANGLE OPPOSITE TO EQUAL SIDES ARE EQUAL

THEREFORE QMR = 90 - 60 = 30

therefore PQM = 75 - 60 = 15

PM = PQ because M is the mid point

therefore PR = PM + MQ\cos QMR

                PR = 18(1+\cos 30)

QR = (PR^{2}-PQ^{2}))^{\frac{1}{2}}

PQ = PM\cos MPQ + MQ\cos MQP=2PM\cos MQP

5 0
3 years ago
In
o-na [289]
Answer
D
Hope this help you?
3 0
2 years ago
Two isosceles triangles have congruent base angles. The lengths of a leg and base of one triangle are 17 cm and 10 cm respective
Harman [31]

Answer:

Triangle 1:  Leg 17  Base 10

Triangle 2: Leg ???  Base 8

Set up a proportion:

17 / 10 = Leg / 8

Leg = 13.6 cm


Step-by-step explanation:


4 0
3 years ago
What is the value of v? v/-8=v 4?
Ray Of Light [21]
V/-8 = 4v
V= -32v
V+32v=0
33v=0
V=0
8 0
3 years ago
Read 2 more answers
What is a similar triangle?
statuscvo [17]

\large\text{Hey there!}

\large\text{\bf{Similar triangles}}}\large\text{ \underline{are basically} \boxed{\text{triangles that have the same SHAPE}}}\\\boxed{\large\text{but they can still be different. They can still be similar if one them  is}}\\\boxed{\large\text{rotated or one of them is reflected image of the other triangle}}\checkmark

\large\text{Good luck on your assignment and enjoy your day!}

~\dag\dfrac{\frak{LoveYourselfFirst}}{:)}

5 0
3 years ago
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